Empirical equations predicting Newman Motor performance

[jadaro2600]

You can regionalize the magnetic field ..four north on one side and 4 south on the other, this will create lines of force between them in an more even fashion.

[kmarinas86]

Hi Kmarina thanks for response. Do you mean I should do four on one side and four on the other side?
Can I place them evenly on a round rotor with space between NNNN SSSS or it does not work that way?
Thanks

It will be weaker that way, but it will still work. If you want to do this, you might as well focus on the strength of the coil to make up for it. Start with a square coil, unlike what I did. Then you could use a cylindrical column. It will look like a window motor:

http://www.youtube.com/results?search_query=window+motor&search_type=&aq=f

Keep in mind that if you use a weak magnet, your motor efficiency will be compromised. Also, if your magnets are tiny compared to your coil, you can expect your motor to run a long time, but mechanical output power will be small.

The commutator is the most important bit. You want to generate the cold spikes. The generation of cold spikes is enabled by several things:

1) Large coil thickness (important for obtaining higher inductance/resistance which will increase the impedance (i.e. voltage/current) of the flyback)
2) Higher voltage
3) Spark gap
4) Flyback current (do not confuse this with back-emf)

If any of the above items is compromised you will have a harder time achieving Newman's observations.

[guruji]

Thanks Jadaro and Kmarina for response. Maybe if one do not include wood in the rotor and do it with metal would be better for magnetisim.
Regarding the circuit I am going to use that of Peter Lindemann.
Thanks guys Happy Christmas.

[kmarinas86]

http://www.youtube.com/watch?v=3KtqdUOzh2g

FAN:
Flex-a-lite Heavy Duty Division
32" 6600 Series - .625" pilot - no bolt holes

POWER:
242 volts
0.035 amps
8.5 watts

RPM:
120 RPM

Fan tip speed:
11.4 mph

[kmarinas86]

Also, another thing I am realizing is that the cooling ability has a non-linear relationship with the back-spikes.

I have observed "measurements" of large negative spikes over 0.7 "DC" amps on my digital Extech 411 multimeter. With this was often a lack of proportionality in the cooling effect. As we should all know from science, all current, no matter what direction, produce heat.

The energy of the flyback has basically two ways to be used up through the circuit:

1) As heat.
2) Output power through the fan.

It turns out the anomalous mechanical power output is not highest when there are large negative spikes, but rather, it happens when the current going either direction, is kept low relative to the voltage.

As I have said before, the impedance relation (i.e. voltage/current) of the flyback should be greater than that of the input.

Theory of the electric field in motor windings:

If the electric field changes rapidly, it will create a residual magnetic field that is circular around the wire. A small amount of coulombic energy, dumped for a short amount of time, is the result of a large voltage slew rate. The electric field strength is the ratio of the voltage divided by the distance over which is it diluted.

The energy density of the electric field is:

(1/2) * (efield)^2 * (electric permittivity)

Expressed in another way, this is:

(1/2) * (volts/length)^2 * (electric permittivity)

The fluctuation of the energy in the electromagnetic field is converted between electric magnetic and magnetic fields. Thus, over time:

(1/2) * (volts/length)^2 * (electric permittivity)

is proportional to the magnetic field potential energy density:

(1/2) * (amperes/length)^2 / (magnetic permeability)

Thus the field that can be generated is a function of:

(1/2) * (volts/length)^2 * (electric permittivity) :: (1/2) * (amperes/length)^2 / (magnetic permeability)
(volts/length)^2 * (electric permittivity) * (magnetic permeability) :: (amperes/length)^2
(volts/length) * ((electric permittivity) * (magnetic permeability)) :: amperes/length

Where "::" is symbol representing proportionality. In mathematics, its lowercase alpha "α" (which doesn't show up well in Tahoma font).

The volume of a wire can be related to its resistance by the following formula:

resistance = resistivity * length / cross-sectional area
resistance = resistivity * length^2 / (cross-sectional area*length)
resistance = resistivity * length^2 / volume
volume = resistivity * length^2 / resistance

Thus the energy in the electric field in a thin wire is equal to:

[(1/2) * (volts/length)^2 * (electric permittivity)] * [resistivity * length^2 / resistance]
[(1/2) * volts^2 * (electric permittivity)] * [resistivity/resistance]
[(1/2) * resistivity * (electric permittivity)] * [volts^2/resistance]

So the energy stored is determined by the three following factors:

1) resistivity
2) electric permittivity
3) volts^2/resistance

"volts^2/resistance" in an inductive circuit is not itself a measure of power, but rather is it factor of proportionality determining how much power may actually be involved, and this is relative to the resistivity of circuit and its electrical permittivity.