Electrical igniter for gas engines A keystone to understanding by Magluvin

[poynt99]

Hi p.99

My question is very precise

As those 2 pieces of wire, has a small but real resistance , they should from themself destroy 50 % of the tranfered energy anyway,    as they do in a normal transfer ,  i mean , without the inductor . Right ?

You are correct in the previous, but not in the above quoted statement.

I have already posted this information, but sometimes it takes a while for things to sink in. It is also fully explained in that document I referenced.

When you introduce an inductance, you want to use an inductor of relatively high Q factor; that is the ratio of the inductor's inductance divided by it's resistance is high. For example, if we have an air-core coil of 100 turns using 14AWG wire, we may have an inductance of only 40uH, with a DCR of say 0.05 Ohms. If we insert a high permeability core, the inductance may increase by a factor of 1000, yet the DCR remains the same at 0.05 Ohms. This latter coil will have a Q factor roughly 1000 times higher than the air-core.

Once the inductance becomes appreciable, the impedance it presents to the circuit dominates the impedance of the wiring, and so rather than the energy getting burned up in the wiring, it gets absorbed by the inductor (which dissipates very little energy), which then releases it again to the charge capacitor. There will always be some finite resistance and finite and practical inductance, so the process can never be 100%, but we can get very close.

And finally i think that we have to consider not only the inductor , but the  "mariage " or wedding  pair of inductor and diode. because in my real life testing this effect  NEEDS the pair. Without inductor and only a diode= no improvement of the transfer.
without diode and only inductor  = no improvement of the transfer.

thank's to all for the good work

I am very happy to learn so much with you

and good luck at all

Laurent

Yes, for energy transfer the diode is required.

.99

[woopy]

Ouups P.99

i fergot the precise question

I precisely ask you if you can explain me how the pair of      inductor -diode stores energy without  lost in the BC, are they almost supra conducting ?, and if not how can they store so much energy to overcome theyre  own resistance plus  the resistance of the adjacent wires and the associated tremendous 50 %  lost ?

i hope not to be ridiculous here , but 2 years ago i did not know what a electron was , and be certain that today i always have no more clue 

P.99 i am serious here . I am trying to understand what is going on. So please try to answer my question in words or example or drawings that i can understand.

thank's

laurent

[woopy]

hi P.99
thank's for answering so fast

we are crossing the reply     no problem

I have a small problem to understand your explanation  because you evoke  " inpedance " do you mean that in the " BC " we are in an AC situation ?.
I think we are in a DC situation and in this case we are in a  "resistance " situation.

OK i have to go sleeping

Always happy to learn

Laurent

[poynt99]

No problem Laurent.

Sometimes it is better to think about inductors not in terms of AC or DC, but in terms of what the current is doing.

Ask yourself this question:

"Is the inductor current changing?"

If the answer is "YES", then you treat the inductor as a resistance that changes depending on how fast the current is changing through it. The faster the current changes, the higher the resistance (impedance).

So, in the case of the capacitor energy transfer experiment, the current is changing, and therefore the inductor will offer some impedance (similar to resistance, but frequency dependent and with a phase shift) to the circuit. If the inductance is large enough in comparison to the total wire resistance, most of the energy will be absorbed by the inductance rather than being burned in the total wire resistance. Therefore, more of the energy will be transferred to the second capacitor rather than being lost in the resistive wiring.

Make sense?

.99

[Magluvin]

Hey Point

I will reply to your request, but first I would like to see if anyone else understands where Im coming from with my last post.  Most that have been following here should get the drift in what Im saying. Ive been saying it for a while.  ;]

Woopy? Forest? Anyone?  Do you get my drift?   ;]

Mags