GENERATOR- YOU DO THE IN/OUT POWER MATH

[FatChance!!!]

I believe the reason to the lack of interest is the blurry information.
I haven't found any links to detailed build info and results.
Could you point me to good and specific info how to replicate this device?
I'd love to replicate if I had access to all the details without any hidden parts.

And I have the dough and and resources for a heavy duty replication.

[DeepCut]

OK i've taken some pictures and i'll do a video after posting this. My video quality is crap but the pictures are high-res.

What you need :

1. A DC power supply. I have a PSU but obviously a battery could be used.

2. A Bedini circuit. But since we're not charging batteries here you just re-route the wires that would normally go to the battery that would be being charged. As i was able to do this i'm sure i don't need to explain how to anyone here but here's a picture of my old Bedini circuit with the rerouted wires, bear in mind this is not the setup under discussion but just a picture that had the Bedini circuit in it :

http://qvision.pwp.blueyonder.co.uk/bedini.no.charging.jpg

3. A drive coil. This is the small coil you see in the above picture. This coil is bifilar wound, the red wire is the trigger wire and the gold wire is the power wire. When you start the magnet rotating at first by hand, this causes a tiny charge in the red wire via induction, this then activates the transistor in the Bedini circuit to let in the main supply power which goes down the gold power wire and gives the coil a magnetic field strong enough to repel the magnet. My trigger wire is 0.25mm and my power wire is 0.28mm but there is a large tolerance when it comes to the wire gauge. I did 800 turns of both wires. I found an air ore works better than a ferrite core.

4. A rod-shaped neodymium magnet that is diametrically magnetised. This means that rather than North and South being at either end of the magnet, each curved side of the magnet is North and South, it is magnetised through it's diameter rather than it's length. This magnet also needs a hole through it's length so it can be mounted on a shaft. The hole in my magnet is 6mm, here is a picture :

http://qvision.pwp.blueyonder.co.uk/magnet.on.shaft.JPG

I copied Tom and use 6mm carbon rod for the shaft because it's light.

5. A pickup coil. I used 0.25mm wire, same as the trigger wire. My resistance is 90 ohms. I wrapped it around a cut-off pringles can and made holes in the can for the shaft to go through. Here is a picture :

http://qvision.pwp.blueyonder.co.uk/pickup.coil.JPG

I put insulating tape on the bottom of the holes to stop the shaft rubbing against the wire.

6. A full-wave bridge rectifier to turn the AC from the pickup coil into DC.

7. A capacitor across the rectifier output. Gyulasun called this a puffer capacitor. This gave a great improvement to the output.

I put my Bedini circuit into a project box just so it was tidy, here is a picture :

http://qvision.pwp.blueyonder.co.uk/project.box.JPG

The three wires sticking out of the top are, from left to right :

a. From collector of transistor.
b. From emitter of transistor.
c. From outer leg of potentiometer

I'll do a video now and stick it on youtube.


Thanks,

Gary.

[mscoffman]

...
I wnted to know, purely, the watts in vs the watts out without measuring current with a resistor load bla bla so i did what you said before, read the voltage with a DVM and calculated the current because the coil resistance is known.
...

@Deepcut

You have learned a lot I think, and this is good.

But I have problem with the above measurement scenario.

The output circuit need to be divided into two parts;
the coil that operates on the AC signal and the rectifier
bridge and cap filter that operates on DC signal.
What you are trying to do is use the DC resistance
on the AC side of the circuit and this is *incorrect*.
The resistance the AC signal sees is called (capacitive
or inductive) reactance. The coil is an inductor so
the resistance that the AC signal sees has to be the
inductance of coil combined with the frequency of the
AC signal, which is also the speed in REVS per Second
that the rotor is turning.

The only way to do what you are doing is to know the
resistance that is the same as effective resistance of coil
at the AC frequency. So you can't skip the full DC analysis
of the power. Once you have measured the true DC power
correctly -> then you can calculate the effective AC
resistance of the output coil at frequency and use
that in the future and I guarantee it is going to be significantly
higher resistance then the DC resistance of the coil.

Because you are using a significantly lower effective resistance
in your calculations the actual numbers you calculate are erroneously
showing more output power and therefore a higher COP than you
actually have. This doesn't mean you have no overunity COP as
there may or may not be some left.

Which is why self running device is the gold standard for overunity
energy production.

:S:MarkSCoffman

[DeepCut]

Mark.

I don't like you anymore !

Just kidding

Damn i knew it was too good to be true ...

So, how do i do the proper calculations ?

Oh, and here is a link to the video, i've just put it up so it may take a minute or two to be there i don't know :

http://www.youtube.com/watch?v=a7LbB7FWfO4


Thanks Mark, for teaching

btw i found this, i think it's what you told me so i will learn it :

http://www.tpub.com/neets/book2/4a.htm

those NEETS books are great, nice one US Navy

Gary.

[DeepCut]

Well thankfully the inductive reactance formula is simple.

I don't yet have an LCR meter though

I need to get one that measures frequency as well.

This free-energy isn't very free is it ? LOL ...

Can inductance be derived from other known properties maybe ?

Sorry, i'm posting when i should be googling !

I have a job to go to this evening so see you later tonight or tomorrow.


Thanks,

Gary.