Chalkalis Gravity Wheel

[ae_vector]

@knovos, your calculation for the location of your main weight is correct: 300 * 0.4554=137 mm (13.7 cm). But the equation for one center weight, if the outer weight is known is: 1125 = 0.1 * (w * 2) solving this equation 1125/0.2=w =5625 g for one center weight. That's very heavy for a small unit. Your would need a strong heavy frame. I would recommend getting rid of one of the copper tubes and halfing your center weight to about 2810 g. By the way, 20% or 1/5th of one center weight is the same as 10% of the sum of both weights.

-brian

[ae_vector]

Here's the frame for the swing arms. As I said earlier, it is about 3.5 feet tall and 3 feet wide. I will put horizontal cross-beams in the middle and mount the bearings at the center of the crossbeams where the axis of the rotor arms will be. At the bottom, I made some space to put weights for securing it down during rotation, and maybe strap some car batteries at the sides.

-brian

[knovos]

@ae_vector Thanks for your suggestions, I will go for the option to remove one tube. Like you said the weight is now already very heavy for such a small swing part. Your under construction looks good, simple and with the extra weights on the bottom it should be solid enough.
Keep on going!
Knovos

[ae_vector]

@Knovos, yes, even with my 1.5kg center weight it seems heavy, especially if it's rotating 300 rpms. Here's some pics of my outer weight. It is a 1/2 inch square tube I manually bent using the center weights bolted on the side of the frame for leverage. I plan on covering the swing arms with the circle cardboard you see. This is to prevent accidental severing of my limbs if I happen to slip between the swing arms and the brace. This device is like a guillotine if you're not careful.

-brian

[ae_vector]

@w32 or @knovos, Do you know if the 42 degrees (where the drive wheels are located) is 42 degrees from the horizontal or is it 42 degrees from vertical? Here's a picture to show what I mean.