Captret - Capacitor and Electret

[NickZ]

  In my Captret projects that I did about a year or so ago, I found that no matter how I used or wired the several 8 or 10 caps used, the load, especially if using more than a single led,  would always still drain the battery.
  Although there may be something to this Captret effect,  all I saw was bulging capacitors, and loss of both voltage as well as current in the batteries.
  Good luck with your tests.

[Rydan]

Hey guys, just thought I'd add my 2.5 cents about some observations with the captret idea that ibpointless has posted, regarding my own observations from my own experiments.

While it is true the captret loves voltage, it does not like batteries connected in series as the source. I found that the captret can 'see' the source (if it is in series) and will always drain the cap and batteries.

I've found that the captret can power loads for an incredibly long time, but the end result is a totally dead battery.

I will give an example: purchased brand new energizer headlamp consisting of 3 high bright white LED and a single NIGHT Red LED.
It comes with 3x 1.5v batteries unsure of ma/h. It says on the packet that these brand new batteries will power the device on 'White' LED mode for 23 hours.

I connected up a 9v battery reading about 7v to capacitor in normal captret style to power the Light. (powered it in white led mode)
To be fair I'd say that the light coming out of the Device was around about 1/3 of what it would be if it was operated normally with all 3 batteries powering it.

I ran this light at same intensity of about 1/3 brightness for 970 hours,  then the light faded. When I disconnected the battery and measured it. It read in the millivolt range giving random readings. It was like every bit of energy was sucked out of it.

I've found the best use of the energy from the captret is connecting a cap directly to the battery as you would normally to charge it up p-p and n-n. What happens here is that yes the battery will drain somewhat then rise back up and then surpass its starting voltage. then you just tap off the positive and can whilst still connected to the battery. The battery will not drain once the cap is full, it will actually charge. If you connect batteries in series the captret will see the source.

Like Ibpointless pointed out, the captret will power small led's ect for a while  but eventually the power will dissapate as it needs to rest to recharge. So pulsing the power seems to be the go.

This charging effect in parallel arrangement works  well with caps of any voltage and capacitance, however with batteries for the charging effect to work the batteries need to be matched in voltage. I'm not 100% sure about capacity, but have noted  different voltage batteries just drain.

Another thought I had was, well 'If only I had a capacitor that held its voltage without draining, we could tap the captret part forever'. So I theorised that If I charge two caps in parallel from a source and leave them connected in parallel, it might exhibit the charging effect and maintain the voltage. It dosen't. The caps are converting energy from the environment, and they will only start drawing this energy in if the are at a lower potential then the enviroment. Ie; mv. the only way I know how to do this is connect a cap to a battery (and leave it connected) and tap off the captret. I read somewhere on the web that eveready makes a 300v battery, which would be good for a source. I'm not sure if it would work as it is not lead acid, but worth a look anyway. I might buy one next week and see.

I connected 4 caps of different voltages (from 10,000uf to 680uf) and capacitances that had been sitting around for a while. (I shorted them all before starting) Connecting them all in parallel and left overnight. I noticed they hit to 200mv range fairly quickly, within an hour or so of connecting up and a test a few minutes ago theyre at 0.34v and climbing, albiet slowly. I don't know how far these caps will charge on their own.

Hypothetically,  if they were leftalone and somehow did charge up to 2-3v or more, that would be something, but take an extremely long time. I think if we had 50-100 or more caps in parallel doing their environmental charge thing, we could have a circuit to switch from parallel to series every so often. Sure it would require a battery, but just for switching. That way, with say 100 caps drawing in a mere 50mv , you could have a 5v discharge at a resonably good frequency, or for a rediculous amount of caps, you could probably achieve a constant ouput. (Oh, and for anyone interested, I've tested this cap charging effect in the middle of the desert, no where near towns, radio transmitters or anything remotely electrical, and it still works

Anyways cheers to Ibpointless, and others who have been working on this idea, it has a lot of potential.

[schuler]

  Hello Explorers.

I've done some experiments with captret and I conclude: it's very interesting. But at the same time, I can measure current flowing out of the battery and in the end the LED goes off. So, I believe that there is no OU.

Diodes in general and LEDs in particular are very interesting devices. One remarkable aspect of LEDs is:

According to their calculations, as the voltage is halved, the input power is decreased by a factor of 4, while the emitted light power scales linearly with voltage so that it’s also only halved. In other words, an LED’s efficiency increases as its output power decreases. (The inverse of this relationship - that LED efficiency decreases as its output power increases - is one of the biggest hurdles in designing bright, efficient LED lights.)

Source: http://www.physorg.com/news/2012-03-efficiency.html

The lower the voltage, the more efficient LEDs get. CAPTRETs are very efficient at powering LEDs and at the same time are efficient at extracting energy from a battery. So, it seems to me that Captrets are not source of OU, but they are very interesting considering the way they extract energy from a battery.

[dxer_87]

ibpointless, What You found are 2 things.

1. The capacitor have more capacity than only between + and -. And the additional capacity is between the case and one of the electrods. That's normal. It is even possible to measure this capacity by typical meter. You showed in the first video that the voltage don't drop from the appropriate capacitor. This is a proof that in one cap we actually have two independent. The one between (o) and (-) electrods is just another one with some percentage of capacity of the major cap. The charge in this cap is not because gathering a signal from ZPE or Aether or anything unproved. The charge was supplied when the major capacitor was charged (or recharged by itself) and this is due to imperfection of the cap. So as you mentioned, anyone can use this additional capacitor that is giving some more capacity than the major, but still, the charge comes from the source (because charging process is not 100% efficient and some part of the charge goes to our extra capacitor made of the shield).

2. Capacitors just like batteries are recharging by itself. Because of chemistry inside of a cap (similar to the one in cell battery) processes of recharging itself exist and if battery is in good condition, anyone can try to dissipate this energy from time to time. Still this is not overunity, this is energy coming from chemical processes inside of the battery/cap. But even if this is not OU, it's some kind of free energy that anyone can use. This self recharging effect is exhuastible due to condition of a battery/cap.

I hope I made it brighter. ibpointless, I think it is not about OU to say about third electrode, it is about making electronic much more real than it is in theory. Good job, I think someone should give a try with used cell batteries. I just found energizer 1,5V AAA from 2002 with 1,423V inside. Not that bad to give them second life. I even recharged alkaline battery with very low currents and some of them recharged very well working with small radio unit.

[Pirate88179]

Hello Explorers.

I've done some experiments with captret and I conclude: it's very interesting. But at the same time, I can measure current flowing out of the battery and in the end the LED goes off. So, I believe that there is no OU.

Diodes in general and LEDs in particular are very interesting devices. One remarkable aspect of LEDs is:
Source: http://www.physorg.com/news/2012-03-efficiency.html

The lower the voltage, the more efficient LEDs get. CAPTRETs are very efficient at powering LEDs and at the same time are efficient at extracting energy from a battery. So, it seems to me that Captrets are not source of OU, but they are very interesting considering the way they extract energy from a battery.

Just a point.  With the work we have done in the JT topic...we learned that leds LOVE high voltage, pulsed as the JT circuits do.  You get more light, and less amp draw then with the conventional designs...and yes...it too will almost totally drain a battery....which is good as you can use "dead" batteries as I do for lighting. (they are free)  This is how I was able to light 400 leds, each one of which "required" 3 volts and 20 mA's using only a JT powered by a single "dead" AA battery.  There may be a relationship here between the JT and the captret circuits....I am not sure.

Bill