Idea:  why not use the explosion to create compressed air, and then run engines on compressed air?  This might be easier to get off the ground and running.  If we build a pressure vessel with a spark plug, pressure sensor and pressure relief valve - we could fire the spark as often as need to maintain pressure. 

Danger! Only qualified people should try to build a pressure vessel - it could be a lethal bomb. 

Quote from: gotoluc on July 02, 2008, 01:24:04 AM
Hi Dr. Stiffler, that sounds amazing. Looking forward to a video

At everyone, today is Canada day and I worked all day on the circuit and found something new. The flash of the spark is so bright that I cannot look at it anymore. You cannot see this too much in the video but look at the wood board the spark plug is on, it turns blue. Also look at the last frames and you will see the flame come out of the plug over one inch.

Please look at the new video: http://www.youtube.com/watch?v=thV6QgXHz7A

S1R has told me that when I have the kind of spark he has I would need sun glasses to look at it. I need to do more tests before I can say if this is the real thing.

Please stay tuned for updates.

Luc

Hi Luc,

Yes, SR1 said the same thing to me too. I can tell you that on the device I showed using a 20Hz sig gen with, if I used a 100uf capacitor instead of a 10uf capacitor, the discharges on the spark plug were so large, bright and continuous that they effectively blew the water spray away from the plasma before it could make contact and no explosions were observed. This makes sense. This is why such higher power tests are no good out in the open. But in the confines of a pressurised cylinder, by forcing a larger amount of water and moisture into the plasma with pressure, I expect we should get a much larger explosive result. And if there is any chain reactive effect in the explosion when pressurised, this should cause a great deal, if not all of the moisture in the cylinder to explode and we should see an exponential increase in output power. A number of us are now working on this....

Regards,

Ossie

It would seem the energy available is basically the Latent Heat of Evaporation as liquid water converts to vapour.  The latent heat of water is known to be 2260 Joules per gram.  1 Joule is 1 Watt per second.  Therefore exploding 1 litre (1 kg) of water into vapour has the maximum potential to supply 2,260,000 Watts for 1 second =   627 Watts for 1 hour. 

1 horsepower = 746 Watts. 

Hopefully we could get an efficiency in the range of 33%.  So it would appear that we could get some useful power out of this - but it would probably chew through the water.  Although that disagrees with the anecdotal evidence that water requirement is much less.

Or maybe i'm completely wrong.  Just trying to get a conservative guess for the sceptics.

Quote from: callanan on July 02, 2008, 02:13:20 AM
Hi Luc,

Yes, SR1 said the same thing to me too. I can tell you that on the device I showed using a 20Hz sig gen with, if I used a 100uf capacitor instead of a 10uf capacitor, the discharges on the spark plug were so large, bright and continuous that they effectively blew the water spray away from the plasma before it could make contact and no explosions were observed. This makes sense. This is why such higher power tests are no good out in the open. But in the confines of a pressurised cylinder, by forcing a larger amount of water and moisture into the plasma with pressure, I expect we should get a much larger explosive result. And if there is any chain reactive effect in the explosion when pressurised, this should cause a great deal, if not all of the moisture in the cylinder to explode and we should see an exponential increase in output power. A number of us are now working on this....

Regards,

Ossie

Hi Ossie, thanks for your reply. I must tell you that I have a very different circuit to do this now.  I am using only one 1uf capacitor to do this at around 110 volts input and no inverter. I have a variac going though a 1 to 1 Toroid which I use as an isolation transformer which goes to the FWBR to feed the new circuit.

So now I know for sure that it is not something special in the inverter that will give the effect.

Can you test your setup with only 1uf at 110 volts and see if you get flashes that are too bright to look at and you can spray as much water as you want and it keeps working?

Let me know please.

Tomorrow I'll see if I can measure the current draw.

Luc

Quote from: gotoluc on July 02, 2008, 02:54:55 AM
Hi Ossie, thanks for your reply. I must tell you that I have a very different circuit to do this now.  I am using only one 1uf capacitor to do this at around 110 volts input and no inverter. I have a variac going though a 1 to 1 Toroid which I use as an isolation transformer which goes to the FWBR to feed the new circuit.

So now I know for sure that it is not something special in the inverter that will give the effect.

Can you test your setup with only 1uf at 110 volts and see if you get flashes that are too bright to look at and you can spray as much water as you want and it keeps working?

Let me know please.

Tomorrow I'll see if I can measure the current draw.

Luc

Hi Luc,

If you are using 110V from the wall and your 1:1 toroid transformer is big enough, all you are seeing is a standard arc discharge as that in an arc welder. The ignition spark will simply be providing the ionisation for the arc to start. Just as in arc welders that have a HF spark start so that you don't need to touch the electrode and risk sticking to get the arc going. So you will find that your input energy will be significant. That is not to say that this won't be effective to test on an engine as I think it might be a good and simple test rig to prove that you can fire an engine with water in the cylinder. But I don't think it would be an efficient way to get an engine running on water in a stand alone setup. For this we need to get the electrical energy input down.

I have also gotten such an bright arc effect like an arc welder by using my simple security strobe setup/circuit and connecting 5 or 6 12V lead acid batteries in series with a large HV diode (diodes) across the spark plug. Yes the spark plug will glow red and perish and it will use heaps of input energy and be nothing more than a brute force device.

Regards,

Ossie