Quote from: broli on November 20, 2008, 06:12:18 AM
I think that's an illusion, you might have noticed by now that Stefan decreased the amounts of posts that are shown per page.

Stephan created free postings .. amazing 

Quote from: AbbaRue on November 20, 2008, 01:20:38 AM
There is still one thing that puzzles me about the Young Effect.
Something I haven't seen anyone comment on yet.
Even Captainpecan didn't make mention of it.
What about the energy that is conserved when you charge the capacitor up through the motor? 
I placed the motor between one lead of the batteries and the capacitor and the motor ran for quit some time
before the capacitor was charged up. 
Now we have many turns of the motor and a charged capacitor. Which can then be used to do some more work.
Instead of destroying the charge put out by the battery while running the motor,
we store that energy in a capacitor.  The Larger the capacitor the longer the motor will run before the capacitor is charged.
The dead short of a dead capacitor makes for a good jolt to get the motor spinning,
Then as the motor speeds up the resistance of the capacitor starts to go up as well.
Once the motor is moving at a good pace what would connecting another dead capacitor up to it do?

Perhaps this would have some value?

AbbaRue,

Yes, that is to be expected isn't it? Normal stuff, but it's not a way of obtaining free energy.

That's like stating "if I run a single motor off a battery, this costs me energy, but if I now insert a second motor in series with the first, the second motor will run for free and I still get the same power and torque from the first"

It doesn't work that way, and neither does the capacitor scenario you outlined above. There is no energy gained, it is conserved.

Remember the one cap and two cap scenarios? The one cap scenario the way Captainpecan is doing it is extremely wasteful, and because of this, the scenario two appears as though a gain of energy occurs, but of course it does not. Apply a short pulse in scenario 1. You will get the same "work" done on that rotor, yet you will still have voltage on your cap!!! PROVE JUST THIS ONE THING TO YOURSELF!

Curious that Captainpecan has not made one single rebuttal to any of the facts I've pointed out. I hope he takes the time to do some of the tests, or at least think through some of them.

I am a free energy enthusiast, but I will try my damnedest to explain any anomaly I see on the bench before making a OU claim. Otherwise you just haven't done your due diligence and odds are that you've overlooked something which is going to come back and bite you. I hope you've got your Kevlar suit on Captainpecan.

Poynt99

poynt99, they are building circuits that helps us recycle energy so let them do what they are doing regardless of what they think they are doing. If they think it is free energy, let them think that because no matter what, we are all still benefiting from it. Think about it. 

Poynt99

My hats off to you. You have a lot more patience with stubborn researchers than I.

I stop when the person I'm trying to convey information to is unable to be influenced.

This dual cap charging scenario gets replayed every now and then by people without a 101 course level of understanding of very basic circuits and energy transfer.

But they plow on doggedly hoping for success, stating that the foundation of electronic physics is all wrong...further that all the engineers in all the labs in all the worlds missed this one and they will show the world differently.....an old saw.    Just a case of angry scientist syndrome

I wish I could steer all that energy in a useful direction.

Captainpecan is attempting to be a real scientist by careful note taking, I applaud him for that as many do not go that far.

But if the test setup or basic understanding is flawed, you can take notes and data as skillfully as an accountant and still the data will skew in the wrong direction.

Kudos......HD

p.s. to his credit he has begun to see the folly of the motor as output  test device as pointed out by Yucca recently and myself in several earlier posts.

@All,

I have completed my circuit today. The unit is up and running after some fixing of bugs in the mcu firm ware.
Attached is the circuit drawing. I have not made a drawing of the controller part yet but it is a simple PIC16F84A mcu
running at 20MHz. The mcu controls 6 optocoplers that switch 6 transistors on and off. I  will make a drawing
of the controller if anybody ask.

Now the switching method. I use the 6 switches as described in the drawing. The last switch stays close for
the double time of the 5 others. I use a step charge of each stage. 255 small pulses to the switch.  I leave each
switch on for each charge of the capacitors, thus connecting each capacitor in parallel, until I dump all the
paralleled capacitor into a big 22000uF. I precharged the big input capacitor to 0,5 volt before starting the mcu controller.
The mcu is running from a separate 9 volt battery. There is no energy transfer between the switch and the capacitors
because of the optocouplers used.

The big input capacitor is slowly charging up. Now I must STRESS the following:

There is NO way I can know where the extra energy is coming from. It may be RF or I may be picking up mains radiation.
The effect is so SMALL that it is well below the noise level. Further, the big capacitor will not charge to more than 1.296 volt.
It seems to me that above that voltage the losses starts to kick in. I have made a RF scan of the actual activity in my area.
The RF scan chart is attached. I do not have a Faradays cage to test in, nor will I make one because the effect I'm seeing
is so small.

(EDIT-1) After one hour of run the input/output capacitor has start falling in voltage. The voltage has now dropped to 1,292 volt.
          Sorry guys, no free energy in this circuit!

(EDIT-2) The image shows a rechargable 9 volt battery connected to the input/output. I'm now using a big cap instead.

(EDIT-3) The voltage over the capacitor did drop because my switch battery was emty and the switch did not run. :-)
             There is still a very small charging effect.
Regards,
Groundloop.