Quote from: Low-Q on May 10, 2009, 07:37:43 AM
I tried to measure something with my prototype by holding it and spinning myself with a voltmeter in my hand - imagine how that looked like: Dancing with magnets

Anyway, my voltmeter can measure as low as 1 mV, but I did not see anything on the voltmeter. Now I have very few turns, only 10 or so, but very strong magnets. I tried to flip the magnet from side to side like wipers on a car, but faster, and could not measure anything in both AC or DC on the voltmeter. However, if I moved the coil back and forth over the same magnets, I measured up to 5mV.

This means the wire has to cross the magnetic lines in order to get a measureable result. I cannot confirm if there is voltage indicated below 1mV in @brolis setup or not, as my voltmeter cannot measure anything below 1mV.

Vidar

Stick it on a rotor and crank the rpm up and then see what you get. If you still get nothing then we have a problem.

Broli,

QuoteI told you to spin both magnets and conductor together and use an electrostatic compass near the rim of the disk. This will show you whether the rim is more negatively charged or positively charged due to electrostatic induction. You can probably use a different method to show it as well. But if this is the case then this proves the EMF on the plate caused the charge gradient right?

You are talking electrostatic effect and not conductor current. I don't believe you even need a conductor to see this effect.
On one experiment I was working on I was using PVC pipe and some magnets and noticed a large electrostatic buildup on the PVC pipe. The effect was strong enough to rotate the pipe on it's pivot using my finger but never touch the pipe.

This would not work first thing in the morning but would again work after rotating the pipe through the magnets again. It did seem that the magnetic field was causing the electrons to align and move to one end of the PVC pipe.
This was totally an electrostatic effect and I did not think too much about it because I figured it was only a static build up and not directly related to the magnetic field.

In any case, the accumulated electrons would still be affected by Lenz's law, or would they if they are not in a conductor?

This is an example of some Homopolar generator designs showing the suspected outputs and some known outputs. If the last example did produce current it would be over unity so therefore it could be concluded that a magnetic field does rotate with the magnet even when rotated about it's axis.

Quote from: lumen on May 10, 2009, 11:53:48 AM
This is an example of some Homopolar generator designs showing the suspected outputs and some known outputs. If the last example did produce current it would be over unity so therefore it could be concluded that a magnetic field does rotate with the magnet even when rotated about it's axis.

I agree on the first, I don't know what you were smoking on the second one. And what's wrong with the last one it's a classic homopolar generator  . Lumen your homopolar knowledge is a bit distorted. Get some time off and rethink some of the things you're saying because I don't like discussions that do nothing but spread confusion.

I should have noted that the output on ALL these setups are out the axial connections and not at any other point.
Also, you need to look closely at what is moving in each configuration.


#1 setup cannot produce output because both legs of the loop cut the field in the same direction and the output is canceled.

#2 Has output because the loop is stationary and the field magnets are rotating in opposite directions. This configuration still suffers from Lenz's law and as the load increases so will the energy to rotate it.

#3 Will produce no output for the same reason as #1 above it.

#4 If this configuration actually did work then the search for an over unity generator would be over. However because the FIELD ROTATES WITH THE MAGNET there will be no output because the lines of force are never cut by the disk or the external circuit.

This is the setup that I have not tested! It also will prove that the field actually does rotate with the magnet. (If there is no output)