Quote from: lumen on May 15, 2009, 09:17:32 PM
With a stationary field, then any moving object will generate a current AND a back emf. There is no way around this or the current was never generated!

Just the electrons flowing from the center to the outer ring will cause a back emf no matter what path they take.

Please use the quotation function. Because I have no clue who you are arguing with.

Lumen here's an experiment I urge you to perform. Use ferrite beads around the rotating wire to shield it from the magnetic field of the magnet. This may show two things. Either the voltage will be substationally reduced showing that the magnetic field of the PM acts directly on the moving charge or the voltage has not changed at al at the same RPM showing that the fields only interact with each other and not with the moving charges that creates them. Either way this would give a nice conclusion.

With a stationary field, then any moving object will generate a current AND a back emf. There is no way around this or the current was never generated!

Just the electrons flowing from the center to the outer ring will cause a back emf no matter what path they take.
[/quote]
@lumen,
You are now at the center of controversy of induction. 
  Any CHARGED moving object will be induced, not every object.
  Induction neither adds energy to the charged particles, nor takes it away, there is no change in energy in the particle, that is why the magnetic field can do no work.
  Remember the sequence of back EMF; 1: a moving charge makes a magnetic field.  2: That B field deviates/accelerates another moving charge.  3: The second moving charge has a second B field.  4: The second field couples onto the first field causing resistance.
  Nowhere did the first moving charge exchange energy with the second moving charge, and reactionless events took place at 2 and 4.  Also, cyclotrons have no back EMF and induction is definitely happening there.
  The answer to having no back EMF on a large scale is to have a uniform radial current in a disc as is shown in my patent drawing (attached earlier).  There is no other way to do it; this brings the leading edge and the trailing edge of the current sheet around to touch each other (making an infinite width current element) where the fields there cancel each other forcing the secondary field to split into 2 loops (on either side of the disc) and there is no longer a coupling of the primary and secondary field, hence LL violation.  As I said before this happens in nature in all systems of circulating charged particles.
-BWS

BWS I believe I know what you are trying to do now. This is exactly what lumen pointed out as well. Namely having two counter rotating disks.

To obtain what you call current saturation you'd need to adjust a homopolar generator to have theoretically an infinite amount of brushes around the perimeter?

What I don't understand is why you assume there is no back torque. Even though the combined field of the disks adds up to zero it doesn't mean their individual interactions add up to zero with the magnets. They do if the two disks where attached to each other but this is impossible because they are counter rotating.

Quote from: BWS on May 15, 2009, 06:09:30 PM
some further info...
This prototype was made in 2001.  It spent several years at Purdue university where it was nearly destroyed and abandoned.
Nobody there could figure out why the magnet alone generates the highest voltage.  I couldn't find a good powersource so I used a remote controlled radio set with PWM drives.
-BWS

Interesting table of RPM v. Voltage.

But were you drawing a current off this circuit? You should be able to
get a very large number of amps - very large indeed. (In fact, tread
carefully or you will take out your Avo).