Hi,

Thanks for the comments. Yes, it would be worth it to try some JT circuits on the UC to see what happens.

Today I'll add a bunch of features to the data logger software. Broli made a good suggestion.

Paul

A lead-acid battery has an efficiency of only 75-85%
http://wiki.xtronics.com/index.php/Sealed_Lead_Acid_Battery_Applications
So according to the results Ultracaps at 91.9% are much better for all types of pulse motors and circuits then lead acid batteries.

cat

Maybe they should of called it an UltraBattery or anything other then UltraCap. It may have reduced the amount of arguments here. Not all, but a lot.

IST, not sure what you mean by the scope shot. It's only a ringing signal, nothing special, or am I missing something??

One thing about a UC is that it's perfectly fine if it's at zero volts, just like capacitors. Batteries are not. 

UC's are more related to electrolytic capacitors than batteries.

Paul

Groundloop:

No I am not referring to you it was a generic statement, nothing specific to you at all.

Pirate:

QuoteJust put MH on ignore as most of the  rest of us have.  It will save you a lot of time and trouble trying to explain things to someone that does not want to learn.  In his mind, he will always be right anyway so, why waste your time?

How supremely ironic.  This place is supposed to be for exchanging ideas and debating and learning and you want to close your mind and put your head in the sand.

Electricme:

QuoteThanks to Bill, I am now free of the "pest"
I barred "pest" from my PC

Name-calling is immature and inappropriate behaviour.  You never responded to my response to you where I said that a person with your experience in electronics should be questioning Paul's measurements on the capacitor.  I would not be surprised if you are uncomfortable with the whole thing and you secretly agree with me.

You can always put up the pretense of putting me on ignore with your Firefox browser, while at the same time running the Google Chrome browser cookie-free.  Then you can pretend that you are ignoring me and still read me at the same time.  The best of both worlds.

Gadget:

An ultracapacitor is simply a capacitor, and I have given you outside references to show you this.  Don't be fooled by the term "battery-capacitor,"  that's just a marketing term made up by the manufacturers of supercapacitors and ultracapacitors to emphasize the fact that they have a very high energy density by volume and by weight such that they almost "look like" batteries.  It is as simple as that - a marketing catch phrase.  The word "battery" is throwing you off.

Quotewhat  ans poynt99 did not explain why an aa battery by it self cannot charge the bcap but yet it can charge the bcap thru a jt 8 times ??

If you connect a battery directly to a discharged ultracap the battery will have a hard time because the ultracap looks almost like a short circuit.  When you put a JT circuit between the battery and the ultracap then the battery can trickle-charge the ultracap.  Now the battery is not overstressed and it can charge the ultracap.

QuoteIt's not Magic  and the charge process is not an Ou effect but the final  product is the bcap will contain a full charge(BATTERYCAP) and the AA BATTERY Will NOT Require THE AMOUNT OF ENERGY IT WOULD NORMALLY TAKE TO GET THIS BATTERY CAP CHARGED

This is incorrect.  For example using approximate numbers for illustrative purposes:  If the battery ends up putting 1000 Joules of energy in the ultracap by using a JT circuit, then the battery may have expended 1100 Joules of energy to do this.  50 Joules of energy may have been dissipated as heat due to the internal resistance of the battery and 50 Joules of energy may have been dissipated as heat in the JT circuit itself.

The battery voltage may have decreased by only 0.02 volts after this, but that means nothing.  The battery will still have expended 1100 Joules of energy and will have lost a considerable percentage of its charge.  I will say it again:  Batteries are nonlinear devices and measuring the battery voltage can tell you next to nothing about how much energy was just expended by the battery to charge the ultracap, or how much energy is remaining in the battery.  You simply can not use the battery voltage as an indicator of its state of charge.  This is an indisputable fact.

Quoteyou have to put another battery in it to charge your 3.7 volt cell phone or mp3 battery up againg .they dont make one that will charge it up 8 times

Don't loose sight of the fact that if an AA battery can charge up an ultracapacitor up to 2.7 volts about eight times, that means that the AA battery still has a much higher energy density by volume as compared to the ultracap.  You are comparing the volumetric energy density of an energy storage system based on an electric field with one that is based on chemical energy and the chemical energy system wins out and has the higher volumetric energy density.

MileHigh