Quote from: gadgetmall on December 09, 2009, 03:25:04 PM
I got some 30f coming i might try those . And just to add to the "mystery of the Bcap" a bedini will charge them up to full power . No mystery . the high  normaly wasted not in any electronics book BEMF spikes are converted to usable energy in the form of AMPS and VOLTS !

Gadget:

That is exactly what I have been seeing over here as well.  Otherwise, I can find no reason why or how my EB, with 1.9 v, 19mA output could charge a 650 F b-cap to 2.7 volts.  It has to be the spikes and they do appear to store/convert them into usable power.  After seeing all of those random spikes all over my scope this is what I have figured out must be happening.  Also, this explains why, over 2 years ago now, that I could light an led with my original EB experiments (very small electrodes) as I had used a supercap in the simple circuit. (5.5 volt .22 F)

Bill

Quote from: Pirate88179 on December 09, 2009, 04:17:51 PM
Gadget:

That is exactly what I have been seeing over here as well.  Otherwise, I can find no reason why or how my EB, with 1.9 v, 19mA output could charge a 650 F b-cap to 2.7 volts.  It has to be the spikes and they do appear to store/convert them into usable power.  After seeing all of those random spikes all over my scope this is what I have figured out must be happening.  Also, this explains why, over 2 years ago now, that I could light an led with my original EB experiments (very small electrodes) as I had used a supercap in the simple circuit. (5.5 volt .22 F)

Bill

I think so too and i also think three things are charging this bcap up . volts ,current and  spikes from the kick back . and i believe the reason i don't see it charging on the 22 turn secondary is there is one of those three components missing  or too small .This is on a standard Jt . other Jts with more power could do it or maybe its taking a charge so small it can't over come the tiny leakage or the bcap .

Okay gadget:

Here is the Cadillac version for you:

*** CASE 1 ***
Battery percentage of full charge: "%FULL"
Resting battery voltage: "RestV"

%FULL  RestV

100%   1.3 V
90%    1.3 V
80%    1.3 V
70%    1.3 V
60%    1.3 V
50%    1.3 V
40%    1.3 V
30%    1.3 V
20%    1.3 V
10%    1.3 V
5%      1.2 V
2%      1.1 V
1%      1.0 V

So you can be continuously be loosing battery energy and the resting voltage will be the same.


*** CASE 2 ***
Battery percentage of full charge: "%FULL"
Battery voltage when connected to a load resistor: "LoadV"

%FULL  LoadV

100%   1.300 V
90%    1.298 V
80%    1.297 V
70%    1.294 V
60%    1.293 V
50%    1.295 V
40%    1.289 V
30%    1.296 V
20%    1.241 V
10%    1.201 V
5%      1.178 V
2%      1.104 V
1%      0.877 V

So you can be continuously be loosing battery energy and voltage will trend down very slowly, and it might even go UP as you loose battery energy.  The voltage will start to fall off more sharply as the battery nears the end of its life.  The temperature of the battery might be different which is one possible explanation for the voltage INCREASING slightly as the battery loses energy.  Another possible explanation is that the randomly moving molecules inside the battery just by chance expose more "fresh" chemicals that for a short while will give you a more robust chemical reaction inside the battery which will INCREASE the output voltage under load, even through the battery has less available energy in it.

The moral of the story is the battery voltage reading, whether it be the resting battery voltage or the loaded battery voltage, is not a reliable indicator of the state of charge of the battery.  So when you do a test where the battery voltage only drops by 0.002 volts you don't really know what's going on.

However, if you know that your battery is powering a circuit, then you know for sure that the battery is going down in energy, irrespective of the battery voltage reading.

MileHigh

Quote from: gadgetmall on December 09, 2009, 12:08:58 PM
Hey paul For your experiment to be Valid you need a fairly NEW NI/mh 2500 ma rechargable Energizer or equilivent .

I've hardly used my NiMH batteries. As far as size difference between 2000mAh & 2500mAh, it's probably only a difference in the amount of material in the battery. That's why AAA NiMH have much less Ah ratings than the AA made by the same company. Same material, just less of it. For instance I could place two of my AA batteries in parallel to get more Ah. 

Anyhow, looks like my NiMH batteries are in good shape, as it's already at 6000 joules and still plenty to go. The predicted value is 10000 joules.

Paul

Paul:

If you have ESP you might get this message through the subliminal bits.

Even small batteries should never be put in parallel.  The battery with just slightly more resting voltage will discharge into the battery with slightly less resting voltage.  The increased heat in both batteries could set up a positive feedback loop and the two batteries could go into thermal runnaway and both batteries could cook and get very sick.

IST:

I looked at your two clips.  That was a jaw-dropping experience.  I just don't know what to say.  Don't put pulsed DC into a coil.  The coil will become a short circuit in no time.

Plus, you sparking display was... <drum roll> basically a hand-held Joule Thief.  Also, that's old-hat and looks like a Carney trick at this point in time.

MileHigh