Quote from: JuJu on June 30, 2010, 07:15:43 PM
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i continue to believe that this luxmeter test is only a "mirage"... it only read brightness, not real power passing the lamp!

It is a way to go forward check after check.
Nevertheless I agree that in any case, OU can be proved only by a self-running machine, measurements are not enough.
For example one thinks that same brightness implies same power. But is it true? It might depend on the current shape and on the frequency components. It seems crazy because the brightness is just due to thermal agitation and thermal agitation is random and should only depend on the excitation power, not on the shape of the excitation signal. Nevertheless it is not as crazy as thinking of perpetual motion  .
So we have to push the measurement protocol to its limits until the possibility to loop the system becomes clear.

Quote from: replicator on July 01, 2010, 03:29:32 AM
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I propose the below diagram to create a DC with fast Graetz rectifier (HER308, 75ns, 1kV) diodes plus filter it with a HV capacitor.
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It should work if kapagen output was pure AC, but there is a also a continuous component that will unbalance the bridge.
May be we could separate CC and AC and use separate loads.
CC could be obtained from an LC circuit with big inductance and capacity, acting as very low-pass filter to remove 50/60 hz
AC could be got from a high-pass filter.

Quote from: void109 on June 30, 2010, 06:28:06 PM
Just want to make sure you see JLN's new video, Luxmeter ~ output power measurement.

http://www.youtube.com/watch?v=Es0F9MaPzC0&playnext_from=TL&videos=1VEGV470fB4&feature=feedu

pin: 172W
pout: 989W

how did the transfer the light outpout to power output of one lamp?

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how did the transfer the light outpout to power output of one lamp?

check at Naudin's page: http://jnaudin.free.fr/kapagen/kapagen33io.htm

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It should work if kapagen output was pure AC, but there is a also a continuous component that will unbalance the bridge.
May be we could separate CC and AC and use separate loads.
CC could be obtained from an LC circuit with big inductance and capacity, acting as very low-pass filter to remove 50/60 hz
AC could be got from a high-pass filter.

It is true. What we can do with the HF sitting on the pulsed DC (or low freq. AC)? I don't know really, it passed through the rectifier without rectification (unbalance the bridge), but creating filters or resonating transformers it could be transferred the energy from the output side.
The main task should be measure the AC/DC component of the output, but I guess the AC is huge compared to the DC. Creating different filters to the AC components separated by the amplitudes of each "bands" would be a complicated solution.