How about this for an easy test:

Show the circuit oscillating using the FG set to make a negative, long DC pulse, or just continuous DC. Adjust the offset and FG output for best negative mean power oscillations. Then simply uplug the FG's negative (black) output lead from the NERD circuit board. This eliminates any return path from the FG's "probe" to its "negative".

Right? If the circuit continues to oscillate, based on the FG being hooked up only by the red tip lead and not at all by the other lead, that would prove Rosemary right, wouldn't it? And it would prove TK, picowatt, ftc, .99, Stefan, and all the others who believe otherwise to be wrong.
Right?

Especially if both the Grounded LeCroy and the Ungrounded Tektronix (or is it the other way around? I don't recall) both continue to agree like they do in the demo video.

Right?

Quote from: picowatt on May 02, 2012, 04:08:43 PM
With this one statement you prove you have no idea how your circuit operates when the FG output is negative.  Nor will you ever understand how and why it oscillates, nor will TK's viideos demonstrating bias current be of any meaning to you whatsoever.

It is sad really, there was so much that could have been learned.

A saying comes to mind, in paraphrase, "A person who believes they know it all, will not attempt to learn anything".

PW

Maybe this will help.

Although.... psychological research into cognition has shown that as many as 20 to 30 percent of people cannot seem to interpret graphical displays of data. It isn't education or experience or culture, either... apparently it is an innate difference in brain wiring that determines whether the mind can visualise the relationships shown in a graph. Same thing with 3-d orientation in space and map-reading... it turns out that many people just can't do it.


Rosemary.... when people are talking about mosfets operating in the linear transfer region, or when they are claiming that a mosfet can be partially on... they are referring to the data displayed in this graph. The source-to-drain CURRENT passing through the mosfet depends on the VOLTAGE at the gate, and there is a range of voltages at which the mosfet is "both on and off".. that is, it is PARTIALLY conducting and cannot yet be considered "ON" but neither can it be considered "off". The oscillations on the gates in your circuit definitely are of sufficient amplitude to PARTIALLY and very quickly turn the associated mosfets partly on. As soon as they do turn on the amplitude drops and they turn more partly off again, lather rinse repeat. This is the basic principle of an amplifier with gain. If the mosfet was just a switch with only two states ON and OFF you could never use it as an amplifier... and there are a lot of high-quality audio systems with mosfet amplifier stages in them out there.

Quote from: TinselKoala on May 02, 2012, 05:23:17 PM
How about this for an easy test:

Show the circuit oscillating using the FG set to make a negative, long DC pulse, or just continuous DC. Adjust the offset and FG output for best negative mean power oscillations. Then simply uplug the FG's negative (black) output lead from the NERD circuit board. This eliminates any return path from the FG's "probe" to its "negative".

Right? If the circuit continues to oscillate, based on the FG being hooked up only by the red tip lead and not at all by the other lead, that would prove Rosemary right, wouldn't it? And it would prove TK, picowatt, ftc, .99, Stefan, and all the others who believe otherwise to be wrong.
Right?

Especially if both the Grounded LeCroy and the Ungrounded Tektronix (or is it the other way around? I don't recall) both continue to agree like they do in the demo video.

Right?

TK,

This "disconnect the FG black lead" thing will only work if the FG chassis is isolated from (not touching or connected to) another piece of test equipment and that the AC ground is as well isolated.

Don't you think this may be asking/expecting a bit much from some?

PW

What the?

QuoteThis schematic - which TK kindly 'preserved for posterity' - I'm posting it again.  Please do reference this specifically as those legs are 'joined'.  You'll see the absurdity of TK's and picowatt's proposal that current is flowing from the battery supply source through the function generator terminal and probe -  to the the source via the gate at Q2.   It's an adventurous argument.  But UTTERLY impossible.  The Gate voltage can only enable or not - the battery supply source current flow from the drain leg to the source leg.  The voltage at the gate is only and ever an applied voltage signal.  And it is never 'half on half off' as is implied in that Chapter 2 number. That's not possible. 

The only people that state that current flows through the gate of a MOSFET is you Rosemary.

Like usual your technical prose is a confusing mess.  We all need to run for the hills!  Guppy attack!  lol

What you need to do Rosemary is show us a diagram of how the current flows because your prose does not smell like roses to our noses.  Don't you supposes?

MileHigh

Hi Rosemary,

I think it is better to make some new experiment, than to rant here all the time.

Just do the experiments and prove TK wrong if you can do this with your setup...

And show it in videos as he is showing it.

I got again some complains of some users that you only rant here and don´t do the required
experiments.


Regards, Stefan