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Overunity Machines Forum



Testing the TK Tar Baby

Started by TinselKoala, March 25, 2012, 05:11:53 PM

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TinselKoala

And, just to reiterate, I did a manual mean power calculation using a single cycle of that waveform and got a negative mean power of a little over -0.5 Watt. Here are the points I used, minus the grid overlay, and the spreadsheet calcs. Negative values are in red.
This is not corrected for the inductive reactance of the shunt. Since this will be a positive number, a scaling factor, it will only decrease the power value, it will not change its sign.

MileHigh

TK:

Thank you for the effort.  I am starting to visualize the two separate halves of wire that are distributed inductors as per my previous postings.  When the MOSFET shuts off they both start to do their energy burn through the conductive channel of the switching-off field effect transistor that is the MOSFET.   The inductors create high voltage when they do their energy burn.  The top-half distributed inductance goes from 9 volts to 40 volts (or thereabouts) in a blaze of glory, as per what you see on the scope trace.  The bottom-half distributed inductance might also go from ground to -40 volts during it's energy burn.  Hence you can imagine the MOSFET seeing 80 volts across it somewhere in the middle of the burn.

It's this energy burn by these two quasi-phantom inductor temporary power sources that are throwing a monkey wrench into the average power measurement.  It is a disturbance signal superimposed on top of the "regular" operation of the circuit.  Here is the critical thing:  The loads are different.  So you can see there is a fundamental problem with the power measurement right there.  The battery wants to drive Load A, the inductive resistor.  However, when the two distributed inductors are discharging, it's into a different load, Load B.  Load B is a temporary load, the switching off MOSFET.

So you have a single set of measuring instruments to get your voltage and current, but you can't make a proper measurement because there are two different events happening at the same time and they are superimposed, the battery into Load A and the discharging distributed inductors into Load B.  This completely throws a monkey wrench into making your measurements - unless you know what you are doing.

So chew on that!  lol

MileHigh

TinselKoala


MileHigh


WilbyInebriated

milelow, another litmus test fail from you. energy doesn't 'burn'... ::) generally for something to burn it is combined with oxygen.
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