Quote from: Rosemary Ainslie on June 30, 2012, 02:33:12 PM
Picowatt?

Was that excessively long repost of yours intended to take the focus away from this comment of mine?

Not at all, it was intended to again highlight the errors regarding Q1, the basic operation of your circuit, and how Q2, is biased on by the FG...  for those willing and able to learn.

Quote from: picowatt on June 30, 2012, 03:03:02 PM
Not at all, it was intended to again highlight the errors regarding Q1, the basic operation of your circuit, and how Q2, is biased on by the FG...  for those willing and able to learn.

I would strongly advise anyone at all to first establish your credentials before they believe any of your presentations - again with or without respect.

And yet again
Rosie Pose

See how she lies and misrepresents? It's no wonder, though, because she doesn't read words, she just looks at shapes.

AINSLIE: READ THIS _{if you can}:

NOBODY

HAS

EVER

SAID

THAT

A    NEGATIVE VOLTAGE

TO THE GATE

WILL TURN A MOSFET ON.

Again, you hare hallucinating and you are responding to your hallucinations, not  to facts.

A NEGATIVE VOLTAGE TO THE SOURCE, like picowatt has been saying, WILL TURN A MOSFET ON, and anyone can prove this for themselves. I'll even make a video for you, idiot Ainslie. You won't watch it of course, and even if you did you wouldn't understand it, and even if you DID you'd still lie about it or insult someone about it.

If only you were right about something even occasionally, you might be entertaining. But as it is, you are simply useless, a mockery, a parody of yourself. You are simultaneously the most arrogant and the most stupid, ignorant person I have ever met, and I live amongst cholo gangsters.

(People often DO apply negative voltages to the gates of N-channel mosfets; this is in order to assure that they TURN OFF hard. I use this feature in my TinselKoil 2.0 SSTC, where the 4 n-channel mosfet gates are directly driven by the AC, positive AND negative voltages, coming from the trifilar toroidal gate phase transformers.)

MileHigh

Stick to poetry.  Or art.  You're science is not so good.

Quote from: MileHigh on June 30, 2012, 02:51:56 PM
More Bizarro World in the Bizarro Universe:

Rosemary heaping praise on complete beginners and calling them experts (Remember all the praise you had for Aaron when he made his pathetic attempts to replicate your first circuit and clearly did not even know how to operate an oscilloscope properly? (After 10-years worth of playing with one.))....

And at the same time Rosemary bashing and stating that Picowatt doesn't know what he is talking about when he is clearly and expert with many decades of experience in electronics....

You are so morally bankrupt Rosemary that even farthings run away from you.

The mind boggles.

P.S.:  It was fun watching the steam rise from the top of Aaron's head.

And BTW - can I impose on you for some doggerel for my thread?  Be glad of it if you're equal to the task? 

Regards
Rosie

Quote from: Rosemary Ainslie on June 30, 2012, 02:59:50 PM
The appropriate expletive relates to equestrian waste products.  I'll spare you.  You're talking absolute NONSENSE.  I'll SHOW YOU.  Our MOSFETS WILL NOT TURN ON WITH A NEGATIVE SIGNAL APPLIED TO THE GATE.  NOT EVER.  IN ANY WAY AT ALL.  NO HOW.  NOT EVER.  Can I be plainer?

And the balance of your comments are also equally and entirely INCORRECT.

Anyway.  That's it for the night Picowatt.  Ramble on to your heart's content.  You're clearly a rather foolish man that you make claims which will be easily disproved.  But meanwhile - if it satisfies your ego - feel free.  Just know that we've scheduled a whole wack of tests - PRECISELY to discredit these ABSURD statements of yours.  MUCH required - for a variety of reasons.

Rosie Pose.

In the very first paragraph of this response you demonstrate your lack of reading and comprehension skills.

No where have I said a negative voltage is applied to the GATE of Q2 in your circuit.  Are you really that bad at all this?

In your circuit, the gate of Q2 is held very close to ground potential by its connection to the CSR.  To turn on Q2, the FG must apply a negative voltage to the SOURCE of Q2.

That is why you need all that negative offset from the FG...  to bias Q2 on sufficiently.  Note that in all your captures, the FG trace never goes much below -4volts regardless of how much negative offset you apply to the FG.  This is due to the voltage drop across the FG's internal 50 ohm resistor due to the Q2 current flow thru the FG.