Again:



"And may I add - for edification to the picowatts of this world - IF there is a negative signal as NOW CLAIMED -  applied to the gate of Q2 it would NOT conduct that forward biased (clockwise) current flow (outlined in blue) PRECISELY because that NEGATIVE SIGNAL WOULD REPEL the current discharge from the battery supply.  The battery would not be able to conduct.  The blue trace shows the battery conducting."


Please show even one quote where I state a NEGATIVE signal is applied to the GATE of Q2.  You cannot, because no such thing was ever said, by anyone that I can recall, except for you of course.

The gate of Q2 is connected to the CSR and to the FG signal ground.  The gate of Q2 effectively never changes.

A NEGATIVE voltage applied to the SOURCE terminal of Q2 is what biases Q2 on.



   

@PW, .99: (please don't take the ALLCAPS as shouts; I just want to make sure that the blind readers can see as well as possible.)

Ainslie always refers to the mosfets as a "switch". She appears not to realize that the mosfets have a linear conductance mode of operation where the gated CHANNEL between the DRAIN AND SOURCE formed by the ELECTRIC FIELD on the GATE STRUCTURE of the mosfet is REGULATED LIKE A VALVE by the strength of the charge on the gate structure of the mosfet. Hence, the mosfet can also be used as an amplifier, by "tickling" the gate charge around the gate threshold value. SMALL CHANGES in the gate charge result in SMOOTH OPENING OR CONSTRICTING of the GATE CHANNEL BETWEEN THE DRAIN AND SOURCE of the mosfet.

Does Ainslie show any sign of accepting that this mode of mosfet operation is even possible, much less operating as a mechanism in her circuit?

I've taken the liberty of reproducing for educational and review purposes, under Fair Use provisions of the DMCA, a spread from the excellent kindergarten textbook, "Getting Started In Electronics" by Forrest Mims III, published by Radio Shack in 1983. This spread describes what mosfets are and how they work in very basic terms. It should be evident from the structural drawings that the gate structure is one plate of a capacitor, and also that the drain-source channel works like a valved channel, with the electric field from the gate capacitance varying the opening of the valve. I've included it in a large size so that the visually-impaired can have a fair chance at seeing it, if not exactly understanding it.

Quote from: TinselKoala on July 06, 2012, 04:30:35 PM
@PW, .99: (please don't take the ALLCAPS as shouts; I just want to make sure that the blind readers can see as well as possible.)

Ainslie always refers to the mosfets as a "switch". She appears not to realize that the mosfets have a linear conductance mode of operation where the gated CHANNEL between the DRAIN AND SOURCE formed by the ELECTRIC FIELD on the GATE STRUCTURE of the mosfet is REGULATED LIKE A VALVE by the strength of the charge on the gate structure of the mosfet. Hence, the mosfet can also be used as an amplifier, by "tickling" the gate charge around the gate threshold value. SMALL CHANGES in the gate charge result in SMOOTH OPENING OR CONSTRICTING of the GATE CHANNEL BETWEEN THE DRAIN AND SOURCE of the mosfet.

Does Ainslie show any sign of accepting that this mode of mosfet operation is even possible, much less operating as a mechanism in her circuit?

I've taken the liberty of reproducing for educational and review purposes, under Fair Use provisions of the DMCA, a spread from the excellent kindergarten textbook, "Getting Started In Electronics" by Forrest Mims III, published by Radio Shack in 1983. This spread describes what mosfets are and how they work in very basic terms. It should be evident from the structural drawings that the gate structure is one plate of a capacitor, and also that the drain-source channel works like a valved channel, with the electric field from the gate capacitance varying the opening of the valve. I've included it in a large size so that the visually-impaired can have a fair chance at seeing it, if not exactly understanding it.

TK,

Was this in response to her most recent post "over there", or are you psychic?

Yes, it does appear from her newest that she cannot grasp that Q2 is only being turned on "a little bit".  When the FG applies a negative voltage to the source terminal of Q2, Q2 is turned partially on and biased into a linear region of operation.  The amount of DC current that flows, under DC conditions, is approximately 100 to 200ma (that's "milliamps"), with 150ma typically being measured.  This DC current is referred to as "bias current", or simply "Ibias".   

Under these conditions, Q2 is configured as a common gate amplifier.


ADDED:  With 200milliamps of DC bias current flowing thru Q2, the FG, and the CSR, the observed positive voltage at the CSR from this continuous DC current flow, would be only 50millivolts.

If the FG sigal ground is connected to the battery negative instead of the CSR (as was apparently done in some tests) the DC bias current that flows thru Q2 andd tthe FG would bypass the CSR altogether and produce no measureable voltage across the CSR. 

Manny the manual mosfet oscillator and the Magic of DPDT:

(in which the linear conductance range of a mosfet plays an important role)

http://www.youtube.com/watch?v=PIIiKcY3sk8

(ETA: Psychic? No more so than you were with your Higgs boson comment. It's easy to predict her, by now.)

Quote from: picowatt on July 06, 2012, 04:56:50 PM
TK,

Was this in response to her most recent post "over there", or are you psychic?

Yes, it does appear from her newest that she cannot grasp that Q2 is only being turned on "a little bit".  When the FG applies a negative voltage to the source terminal of Q2, Q2 is turned partially on and biased into a linear region of operation.  The amount of DC current that flows, under DC conditions, is approximately 100 to 200ma (that's "milliamps"), with 150ma typically being measured.  This DC current is referred to as "bias current", or simply "Ibias".   

Under these conditions, Q2 is configured as a common gate amplifier.


ADDED:  With 200milliamps of DC bias current flowing thru Q2, the FG, and the CSR, the observed positive voltage at the CSR from this continuous DC current flow, would be only 50millivolts.

If the FG sigal ground is connected to the battery negative instead of the CSR (as was apparently done in some tests) the DC bias current that flows thru Q2 andd tthe FG would bypass the CSR altogether and produce no measureable voltage across the CSR.

Well, it is certain that the video demo of the NERD circuit, which claimed in the video to use one schematic, showed another, was claimed in the paper to use a third and actually used a fourth..... THAT demo, the only one we can trust because there are pictures of it..... had the FG signal ground connected to the battery negative, instead of the CVR. HENCE, the DC current... flowing in the POSITIVE direction, would as you indicate, bypass the CVR altogether and produce no measureable voltage across the "shunt".

What, then, would this wiring arrangement do to the current readings obtained? Would they reflect the true current flowing in the circuit, in the load? Particularly, what would this do to the SIGN of any average current values obtained by looking only at the "shunt" voltage drop?

What assurance do we really have that ANY of the scopeshots were obtained with the FG's negative lead on the correct side of the CVR shunt? Since the importance of this issue is paramount, it needs to be stressed until it's treated satisfactorily by the NERDs or rather, the chief NERD.

I've appended the "original" schematic, the one gestured to in the video by "Donny". One is apparently free to attach the FG's black lead wherever one likes....at point B or point D. Or not at all.

Perhaps it's best if you DON'T attach it at all ...since.... if you don't attach it at all, and if it's like most FGs.... it will be grounded back to the line cord anyway, AND since the scope probe grounds are also grounded in this way it's already hooked to the negative pole of the battery through all the scope probe grounds.
So..... well, if you then DO hook the FG's ground lead instead to the transistor side of the CVR... you will essentially be shorting out the CVR by the groundloop you have just created anyway.