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Overunity Machines Forum



Testing the TK Tar Baby

Started by TinselKoala, March 25, 2012, 05:11:53 PM

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TinselKoala

Quote from: picowatt on July 23, 2012, 07:37:17 PM
TK,

Sorry to trouble you, but could you repost that capture of hers that shows the drain voltage if you have it handy?

I wanted to take a quick look at something and will have to dig for it.

Thanks,
PW

No bother at all, I have everything at my fingertips. The only problem is that there is so much of it.

I think you are referring to this one?

Most of the captures are also readily available here: http://seani.justemail.net/rosemary_ainslie/ 


evolvingape

TK,

A ring and tube system would work well, A Tx ring and an Rx inner tube.The Tx ring should only see the ring section of the Rx tube and calibrate easily. The outer tube is connected to housing  ground earth, forming a nested tubular series cell capable of AC heating for steam, or DC electrolysis for HHO, inside a seamless pressure housing, with a valve at the outlet.

A co-axial chamber arrangement will allow simple piloting via a piston valve for a steam dump injector.

Alternatively a high pressure pulse can be generated by detonating the hho, shaping the flow, and can be either a blowforward or blowback type of valve, initiated by user defined timing of the spark prime mover.

A very simple assembly all made possible by wireless transmission of power. Happy days.

picowatt

TK,

Yep, that's the one.  Thanks!

She seems to think it would take a huge capacitance to pass the indicated AC current at the oscillation frequency.

Looking at that capture, it looks like there is about 150Vpk to pk at the drain.  There also appears to be about 2.6 amps pk to pk of AC current at the CSR trace.

To make the numbers easy, let's call the AC current 3 amps.  That would mean that an equivalent resistance of about 50 ohms at 1.5MHz is needed from drain to source to cause 3 amps to be indicated.

The reactance of 2100pF is approx. 50 ohms at 1.5MHz.  So, assuming a pure sine wave, a 2100pF capacitance would be plenty to pass the observed current. 

However, none of the oscillation waveforms presented in any capture represent a pure sinusoid.  There appears to be a very sigificant amount of at least second and third harmonic present.  For AC currents at the second and third harmonic of the fundamental, the required capacitance to pass a similar amount of current with levels similar to above would be one-half and one-third the 2100pF figure. 

An FFT of the drain voltage and CSR voltage would allow one to quantify how much of the observed current is from harmonics of the fundamental, but visually, I would guess about 20% second and as much as 50% third (looking at FIG4 in first paper).  Using these numbers, 1,500pF would likely be more than sufficient to pass the observed current.


Also note that the drain waveform during oscillation swings to almost zero VDS.  At any VDS < 20 volts, the MOSFET capacitances increase rapidly.  The four Q2 Coss in parallel are only about 700pF at a VDS well over 20 volts, but below 20 volts, total Coss rapidly rises to greater than 4,000pF and approaches 20,000pF as VDS approaches zero.

Ciss also increases as VDS is decreased.  Even at VDS >>20 volts, total parallel Ciss for Q2 is around 11,000pF.  As VDS approaches zero volts, total Q2 Ciss approaches 30,000pF.

1,500pF doesn't sound like a very big capacitance to me, particularly given the large intrinsic capacitances of the IRFPG50.

The way she talks, she would have us believe a huge double layer supercap or similar would be required to to pass her AC current.


PW


ADDED:  3 amps pk to pk of AC current was used in the above example.  In some captures, as much as 4amps is indicated.  However, just as the reactances of the intrinsic MOSFET capacitances are harmonic dependent, so is the reactance of the CSR inductance.

The inductive reactance of the CSR has been determined to be approximately 1 ohm at the fundamental.  However, as noted above, the waveforms are not a pure sinusoids and contain signficant amounts of harmonic content.  For the second and third harmonic, the CSR reactance would be 2 and 3 ohms respectively.  In order to accurately determine the correct amount of current observed by the CSR, an FFT analysis of the harmonic content would be required and all harmonics calculated individually.  However, as signficant amounts of second and third harmonic are readily observed in the captures, it is not unrealistic to expect that the actual current flow may only be a fraction of what is indicated and calculated using only the 1 ohm reactance of the CSR at the fundamental. 

TinselKoala

Ainslie knows nothing of capacitance or capacitors. She doesn't understand them from a practical nor a theoretical standpoint. They are not accommodated by her "thesis" at all. She perhaps grasps that they are some sort of energy storage device.

I used 10 nF (10000 pF) and 1.5 MHz for my capacitance demonstration video. She thinks I faked what I show in it. I am seriously considering using an IRFPG50 as the capacitor in the next video. But what's the use, she is impervious to instruction, even of the very most basic kind.

Like near.... far.

picowatt

You just gotta' love the hypocrisy...

She gets on TK for not posting links to her thread or posting complete quotes, as in this from a recent post of hers over here:

"You omitted the LINK - YET AGAIN.  Here's the little ditty with its addendum that you were so careful to EXCLUDE."

While she on the other hand, snips one paragraph out of a half dozen or so from my recent post and also provides no links to my original comment as she posted that small portion of my comment on her thread.

Guess she wanted to carefully exclude that "Q1 not turnng on in FIG3, 6, and 7" comment from my post. 

Talk about "cherry picking"...