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Overunity Machines Forum



Hydro Differential pressure exchange over unity system.

Started by mrwayne, April 10, 2011, 04:07:24 AM

Previous topic - Next topic

0 Members and 9 Guests are viewing this topic.

wildew

Response to a personal message:
Question was raised about putting ALL of the input water into a narrow vertical tube.
- Close a valve
- Pour in a measured amount of water ( head would be WAY higher than necessary ) it would take a lot more work input.
- Open the valve and let the water flow into the system - is the result any different?

I say No, not with the correct volume added to any diameter tube. The resulting fluid transfer would be the same and the resulting head would be the same. I'm quite sure I could add 2 lbs of water to a 1/2" diameter tube or a 12" diameter tube and if the starting point of the fill was 23" above the base of my current test bed all of the 2lbs of water would enter the system and it would lift 1".

FYI: I only have a 2.5" and a 4" tube set up but yes, it works the same for both of them, the 2.5" just starts with a bit more fill ( same volume though )

Dale

TinselKoala

Quote from: GreenHiker on September 23, 2012, 04:49:10 PM
Both links work for me.  I'm using Internet Explorer 8.0.
This is what the link in poynt99's post looks like, with the "http" stripped off:

api.viglink.com/api/click?format=go&key=0de1c882bae3a5d7344e394b19608218&loc=http%3A%2F%2Fwww.overunity.com%2F10596%2Fhydro-differential-pressure-exchange-over-unity-system%2F2325%2F&v=1&libid=1348354043725&out=http%3A%2F%2Fyoutu.be%2FYwXsoqm75WY&ref=http%3A%2F%2Fwww.overunity.com%2F10596%2Fhydro-differential-pressure-exchange-over-unity-system%2Fmsg337331%2F&title=Hydro%20Differential%20pressure%20exchange%20over%20unity%20system.&txt=http%3A%2F%2Fyoutu.be%2FYwXsoqm75WY&jsonp=vglnk_jsonp_13483540790402

This is what the link in my post looks like with the "http" stripped off:

www.youtube.com/watch?v=YwXsoqm75WY

So..... take your pick. I know which one I'm going to use.

TinselKoala

Quote from: wildew on September 23, 2012, 05:35:57 PM
Response to a personal message:
Question was raised about putting ALL of the input water into a narrow vertical tube.
- Close a valve
- Pour in a measured amount of water ( head would be WAY higher than necessary ) it would take a lot more work input.
- Open the valve and let the water flow into the system - is the result any different?

I say No, not with the correct volume added to any diameter tube. The resulting fluid transfer would be the same and the resulting head would be the same. I'm quite sure I could add 2 lbs of water to a 1/2" diameter tube or a 12" diameter tube and if the starting point of the fill was 23" above the base of my current test bed all of the 2lbs of water would enter the system and it would lift 1".

FYI: I only have a 2.5" and a 4" tube set up but yes, it works the same for both of them, the 2.5" just starts with a bit more fill ( same volume though )

Dale

But is the required input work really different? I don't think so, and that's the point of my thought experiment.  You have the same system with the same amount of water being introduced at the same point, but in two ways that appear to be different at first glance. The work output from the system, including resultant head in the input tube, is the same in both cases.

Is it too much to suggest that a rational person might conclude from this that the input amount of work  _to the system_  is the same, too?


poynt99

question everything, double check the facts, THEN decide your path...

Simple Cheap Low Power Oscillators V2.0
http://www.overunity.com/index.php?action=downloads;sa=view;down=248
Towards Realizing the TPU V1.4: http://www.overunity.com/index.php?action=downloads;sa=view;down=217
Capacitor Energy Transfer Experiments V1.0: http://www.overunity.com/index.php?action=downloads;sa=view;down=209

TinselKoala

Well, my thoughts are going like this right now:  No matter how you add the water, it is going to be equivalent to stroking a small piston a great distance.

Consider, for the sake of simplicity, that Mond's tube cross section was actually 1 cm2 and extended only a little ways above the "max head when lift water is added" line.... I think he's been saying an increase of 40 mm over the "start" position with weight down and before adding the 74 mL of water to lift. And no reservoir, we will just add water directly to the tube itself.

Now add one mL of water to the tube. What happens? It drains down and the weight lifts a bit (1/74 of its final 10 mm?) and once things settle the head in the tube is a half millimeter or so higher than start. What was your piston stroke, a half millimeter? NO.... it was nearly one full cm, _less_ that half millimeter. Your piston has just disappeared into your cylinder, that's all. Now add another mL of water. Ditto. Lather rinse repeat.... for every mL of water you add, you are pushing your "piston" down another (1cm - deltah). Therefore, once you have added your full 74 mL of water, you have pushed down a 1 cm2 area piston, (74 cm - 40 mm) = 70 cm distance. Add your water dropwise, with an hour between drops.... same result, same piston travel, same difference.