well in that case I will correct you!  just kidding but....

First there is not a lack of electrons. There are electrons in the circuit always present, in the metal.

Second you are correct, the EMF of the outer plates do keep the inner plates electrons in place...but this would only be a snapshot of the event at one place in time, if you are using a signal generator, this would be at the height or peak of the sinusoidal signal. As the signal hits the zero point however, there will be no more EMF on the outer plates, meaning the inner plates will want to neutralize. The diodes ensure tha this only happens in one direction....through a load.

In the rotating version, there would be an EMF that holds the electrons in place when the plates are aligned, but as the inner plates rotate away from the outer plates, the EMF no longer affects the inner plates, and again, they try and neutralize, unidirectionally (because of the diodes) through the load.

If you havent noticed by now, the rotating c stack and the solid state one are two sides of the same coin, (and einstein would love this one) ITS ALL RELATIVE! One simply introduces a sine signal, while the other uses a constant voltage and creates the signal through rotation of the plates. I believe the motor to be an easier concept to grasp, and that is why I have placed it here.

Ok, i understand what you are saying, but somehow i cant really comprehand.
like wil the dielectric also be caceled of EMF or stay stuck.
and i know the middle plates want to unload, but i dont know how, becouse there are no extra electrons to to this ( i thnk where would they come from)
somehow i think the one thing will cancel out the other.

hope i'm not a bother    

Not a bother at all!

Picure the inner plates. They are a sea of free electrons. When we place an electrostatic field across them, positive in one side and negative in the other, electrons will collect on one plate giving it a negative charge, while the other plate will have a lack of electrons giving it a positive charge. These electrons are already present in the system, we are just moving them around.

Take a motor and a battery for example, there is a set ammount of electrons in the system. The battery does not add any electrons, it just makes them move. Or take a coil of wire that has a magnet passed across it, the electrons dont appear from anywhere producing current, they were always there, just now they are moving, and the ammount that are moved equates to the amperage.

Oh aha i understand, I was thinke about the C-stack without the motor silly me

Quote from: armagdn03 on August 08, 2007, 09:22:40 AM
a simple way to find out if this is the case is simple. When you had the outer plates connected to the 9 volt, and you shorted the inner plates, was the amperage reading you got continuous, or did it just apear briefly and then dissapear? If it was continuous, there is some sort of pasasge of electrons through all of the plates, if it dissapeared, we still have a potential OU device

So far, so good.
You?re right but the last OU part.

Now, do you remember that I?ve said to take one spoon at a time?
That?s because when trying to take the first, you?ll see it?s already empty.
?There is no spoon.?

But you are already at the second one. How?

It the rotating setup, rotating the plates requires out-side energy. They will not rotate for free, simply by their inertia. The outer voltage will not drop, you?re right, but the motor will always feel the exact extra-load it should feel in order to charge the inner capacitor.

?There is no spoon, really.?

Tinu