Quote from: TinselKoala on July 23, 2019, 07:12:29 PM
That's a lot of energy all right! I wonder what would happen if you overvolted that thing and it exploded, like the one that almost killed me. That cap probably was holding about that same 1 kJ energy when it went, but at a much higher voltage.
450 volts won't jump much of an air gap. 60 kV on the other hand....

Hi TK. Yes, very dangerous stuff!!!

Quote from: nelsonrochaa on July 23, 2019, 07:24:05 PM

Hi TK ,
By accident the pack of 8 in parallel was shorted in the output. I have tinnitus caused by the explosion of that short circuit, is indescribable what happen. the light of explosion  blind the 3 persons in the room under 5 minutes. i could die . Yes very danger when we are talk of capacitors .
I have loan to a friend a 30kv 3uf is the bigger hv cap i have  very danger to better be immersed in oil at that levels .
cheers

Yikes! 

Quote from: Void on July 23, 2019, 07:22:35 PM
Hi Nelson, regarding your video:
Unfortunately I know very little about motors, but I think that motor's power
consumption is rated around 400 Watts under load? Is that right? 
If that is correct, and since the motor is running with no load, then if we take the
motor's power consumption with no load (power consumption due to losses in the motor only) as say
15% of 400Watts = 0.15 x 400W = 60 Watts
If the input power to your radiant device is around 70 Watts, then the setup seems to be performing within
what would be normally expected, but I know little about motors, so I could be wrong with my rough estimation.

Hi Void ,
My crude measurements numbers that i made  , was 342V x 0.30A  each phase . You could calculate .   P = 3^(1/2)   x   V   x   I   x   COS(pi)
But  yes is running in  steady mode in the video .

cheers

Quote from: nelsonrochaa on July 23, 2019, 07:35:00 PM

Hi Void ,
My crude measurements numbers that i made  , was 342V x 0.30A  each phase . You could calculate .   P = 3^(1/2)   x   V   x   I   x   COS(pi)
But  yes is running in  steady mode in the video .

cheers

Hi Nelson. The power factor should be quite low when the motor is running under no load I would think,
but I don't know what a reasonable number for the power factor would be for that type of motor
under no load. My estimation of the power consumption under no load may be off.
I based my no load power estimation on the motor having an efficiency of around 85% (15% losses in the motor).

P.S. Maybe someone out there who knows a lot about three phase induction motors
could tell me if my no load power consumption estimation for the motor seems reasonable or not.

   I once made one of those capacitors made with water in a glass jar wrapped in aluminum foil. I forget their name now, (leyden jar capacitor?) I think, or something like that.  I was surprised at the jolt that even a small 1.5v battery connected to joule thief, to one of those homemade caps can give. It knocked me off my stool, and I threw my multimeter across the room. So much for that meter...   So, even a small input can be dangerous, when dealing with capacitors like those mentioned.

   Nelson:  I don't really know what to say about what is happening in our video, but, it looks like the input is not being affected by the different outputs drawn, that you've shown. I asked if that was correct, or not. As you seam to have a different set up than anyone else, so it's hard for me to understand all that can be happening, or what exactly is going on. I would have to guess, and I'm not very good at that.   Lets all try to be nice to each other, this time around, and have more "funny with friends". And, try to treat everyone right.
   Thanks,
                Nick

Quote from: nelsonrochaa on July 23, 2019, 07:35:00 PM

Hi Void ,
My crude measurements numbers that i made  , was 342V x 0.30A  each phase . You could calculate .   P = 3^(1/2)   x   V   x   I   x   COS(pi)
But  yes is running in  steady mode in the video .
cheers

Hi Nelson for a comparison of my  rough estimate of around 60W (power consumption of the induction motor under no load,
with the motor up to speed, and not including the power consumption of the 3 phase motor controller), here is
a calculation using your rough measured values:

I read that the power factor of an induction motor with no load can be as low as 0.2.
If we take the power factor of your induction motor as say 0.35:
P = sqrt(3)   x   V   x   I   x   power factor
P = 1.732 x 342V x 0.30A x 0.35
P = 62.2 Watts.
That is not including the power consumption of the 3 phase motor controller,
so add some power consumption on top of that for the total power consumption.

Since your input power was around 70 Watts, then these rough estimates seem to be
in the ballpark of what might be expected given the input power consumption, but it is only
a rough estimate. Like I said, I am not very knowledgeable about motors so I could be off on
those estimations.