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Overunity Machines Forum



THE RANT ROOM

Started by ramset, April 25, 2017, 04:30:05 AM

Previous topic - Next topic

0 Members and 9 Guests are viewing this topic.

NickZ

   I don't feel threatened, just insulted. I know that I should just shake it off, but, I guess that is my weaknesses.
   It's too bad none of them will help you out. Those hundreds. You are a one man band here, with nothing to back your claims.       BTW: You did help, now I remember why I left your thread. Not to be insulted once again. I'm glad to see that you "got it".

bistander

EMJunkie posted a copy of this:
Re: THE RANT ROOM
« Reply #147 on: Today at 01:20:53 AM »
Followed by this:
Re: Partnered Output Coils - Free Energy
« Reply #8936 on: Today at 02:07:11 AM »
Quote from: EMJunkie on June 25, 2020, 08:07:11 PM
Thinking Logically is a very important aspect of everyday life! As was pointed out, you need to think in Units of Force and what Force works for you and what Force works against you!


Example:

In a Transformer, totally Symmetrical in its operation, we see Force, or Energy, the same things at the end of the day, are Balanced, Symmetrically. Input Force is opposed by Output Force! Symmetrical!

What does this mean?

In a basic Transformer, we have X Units of Energy being supplied over Time. The Output is equivalent to the Input minus Losses, very simple and Pre-Schoolers can follow this! This means, as a function of the Symmetry in the Transformer, Input to Output Symmetry, the Transformer will ALWAYS be below Unity! It can never ever go Above Unity! Symmetrical Energy Exchanges minus Losses = Below Unity!

It is logical, and is evident, that if we want the Transformer to go Above Unity, then we must introduce Asymmetry, another Force, or another Source of Energy must Enter the Transformer System, and this Extra Force, is required to have a Magnitude in a very Specific Direction!

The M.M.F, in a Transformer is considered Force, its Energy, at the end of the day, and this M.M.F must have Direction to Assist your Input. This means, Force considered as 1 Unit for simplicity equals: 1 + -1 + 1 = 1

NOTE: Simpletons will be removed from the conversation if they interject, do your home work before you show yourself up to be a fool!

In a Symmetrical System, this equation is: 1 + -1 = 0 In other words, all the Energy is used up and no force is left over!

By thinking Logically, and engineering a System as I have shown for a decade nearly, you will be able to build Above unity Machines. Success comes from Understanding, Failure is a result of Not Understanding. Keep it simple, make sure you understand the most simple phenomena! This is super simple, you wont believe how simple this is once you gain this understanding!

Best wishes, stay safe and well in these dire times,
   Chris Sykes
On his other thread where he moderates me off. So I copied and pasted here to ask a question.

Re-quoting from him:
QuoteThe M.M.F, in a Transformer is considered Force, its Energy, at the end of the day, and this M.M.F must have Direction to Assist your Input. This means, Force considered as 1 Unit for simplicity equals: 1 + -1 + 1 = 1

Doesn't this contradict the common practice of summing the mmf around the magnetic circuit to zero? As explained nicely on the attached wiki article. EMJunkie could address this here or on the other thread. I would like to understand this apparent discrepancy.
Regards,
bi

From:
https://en.m.wikipedia.org/wiki/Magnetic_circuit
Quote
Magnetomotive force (MMF)   
Main article: magnetomotive force
Similar to the way that electromotive force (EMF) drives a current of electrical charge in electrical circuits, magnetomotive force (MMF) 'drives' magnetic flux through magnetic circuits. The term 'magnetomotive force', though, is a misnomer since it is not a force nor is anything moving. It is perhaps better to call it simply MMF. In analogy to the definition of EMF,
See attachment.

QuoteIf we apply the analogy to Kirchhoff's voltage law (for magnetic circuits). States that the algebraic sum of the rises and drops of the mmf around a closed loop of a magnetic circuit is equal to zero; that is, the sum of the rises in mmf equals the sum of the drops in mmf around a closed loop
from:

UNIVERSITY OF BABYLON BASIC OF ELECTRICAL ENGINEERING LECTURE NOTES


NickZ

   "not a force, nor anything moving." 
    That's something to think about. I like how that sounds, and what it means.
    Thanks.

EMJunkie




It is amazing how much you sheeple talk about me in this and other threads!

I am flattered!

Even Brain Dead people are starting to learn something of Value! Even if 99.89% of their background knowledge is wrong!

Best wishes, stay safe and well in these dire times,
   Chris Sykes

EMJunkie

Quote from: bistander on June 25, 2020, 10:52:33 PM
EMJunkie posted a copy of this:
Re: THE RANT ROOM
« Reply #147 on: Today at 01:20:53 AM »
Followed by this:
Re: Partnered Output Coils - Free Energy
« Reply #8936 on: Today at 02:07:11 AM »On his other thread where he moderates me off. So I copied and pasted here to ask a question.

Re-quoting from him:
Doesn't this contradict the common practice of summing the mmf around the magnetic circuit to zero? As explained nicely on the attached wiki article. EMJunkie could address this here or on the other thread. I would like to understand this apparent discrepancy.
Regards,
bi

From:
https://en.m.wikipedia.org/wiki/Magnetic_circuit
See attachment.
from:

UNIVERSITY OF BABYLON BASIC OF ELECTRICAL ENGINEERING LECTURE NOTES




Ya godda be kidding dont ya.... and your'e wondering why I delete your posts?