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Overunity Machines Forum



A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1

Started by George1, January 28, 2019, 02:58:40 AM

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0 Members and 19 Guests are viewing this topic.

George1

To lancaIV.
===================
You totally disappont me. You copy entirely the stupid and unskillful Floor's manipulation methods. And it is normally my counter-approach to be the same. Shame on you!
 

George1

To lancaIV.
======================
Prof. S. L. Srivastava's solution is given in our today's post of 12:54:47 PM.
Prof. S. L. Srivastava's solution consists of two lines only.
LINE 1. Current through the electrolyte is given by I = (m)/(Z x t).
LINE 2. Power consumed = (I) x (I) x (R) =  ((m)/(Z x t)) x ((m)/(Z x t)) x (R) = 31.86 W.
---------------------------------------
I am asking you (PERSONALLY!) my question for the 2nd time: Is Prof. S. L. Srivastava's solution correct? Yes or no? Only one word -- either "yes" or "no"!
----------------------------------------
All members of this forum are waiting for your PERSONAL(!) answer for the 2nd time. Only one word -- either "yes" or "no"!


lancaIV

Sie verlieren so viel persoenliche Zeit,George1 !


    Shame on you!  :o  Scham !  ::)  Welch Schwaeche ! Okay, eine Volks-Trauer-Scham-Nano-Sekunde  : Start-Stop ! Genug geschaemt !


   Vielleicht sollte ein " Shame on You/ deontologisch:Fegefeuer/chama "- button installiert werden  ;)



Ich vermute und ziehe deshalb schon vor :




I am asking you (PERSONALLY!) my question for the 3rd time: Is Prof. S. L. Srivastava's solution correct? Yes or no? Only one word -- either "yes" or "no"!





und weil es dann so schoen lang werden koennte :


I am asking you (PERSONALLY!) my question for the ......... time: Is Prof. S. L. Srivastava's solution correct? Yes or no? Only one word -- either "yes" or "no"!






Nach 3 kommt 4 , wenn nicht auf Kommata zurueckgegriffen werden sollte : 3,1 ; 3,11 ; 3,111; ......





All members of this forum are waiting for your PERSONAL(!) answer for the 3rd time. Only one word -- either "yes" or "no"!

"All members ..... " : ich gebe hiermit bekannt,dass ich,als Teil des "All", darauf verzichte zu warten ! BASTA ,nochmoi ! :P


Und ein "persoenliches : Ja ! " beziehungsweise "persoenliches : Nein !"  :




  ICH SO WIE SIE WERDEN NIEMALS INNERHALB EINES DIGITALEN FORUMS PERSOENLICH WERDEN KOENNEN
                                         ( so unter virtuellen 4 Ohren gesagt )


                                         "Only one word" :               oh,da fuehlt man sich Dekaden zurueckgeworfen,Katechese betreffend  :


              Herr(schaften),        nur ein Wort ,                 so wird UNSER(e) Seel(e) gesund


               ALS MENSCH VERFUEGT MAN UEBER VIEL ZEIT, DABEI FREI VON ULTIMATEN SOWIE MORATORIEN


                                                   


Ein schoenes Wochenende wuenschend


OCWL




p.s.: you are refering a Prof. S. L. Srivastava tutorial (hand book) ,based by (rhetorical/specific moment) question/answer examples

George1

To lancaIV.
======================
Prof. S. L. Srivastava's solution is given below.
Prof. S. L. Srivastava's solution consists of two lines only.
LINE 1. Current through the electrolyte is given by I = (m)/(Z x t).
LINE 2. Power consumed = (I) x (I) x (R) =  ((m)/(Z x t)) x ((m)/(Z x t)) x (R) = 31.86 W.
---------------------------------------
I am asking you (PERSONALLY!) my question for the 3rd time: Is Prof. S. L. Srivastava's solution correct? Yes or no? Only one word -- either "yes" or "no"!
----------------------------------------
All members of this forum are waiting for your PERSONAL(!) answer for the 3rd time. Only one word -- either "yes" or "no"!

George1

The text below is a copy of our post of April 24, 12:50:36 PM. (The text below has been published many times in this forum topic.)   
----------------------------
Have a look again at the book "Solved Problems in Physics", 2004, Volume 2, p. 876, solved problem 12.97. The author of this book is Prof. S. L. Srivastava (Ph.D.)
The same book can be found at the link https://books.google.bg/books?id=rrKFzLB9KQ8C&pg=PA876&lpg=PA876&dq=%22electrochemical+equivalent+of+hydrogen%22&source=bl&ots=tQ8PSMLet3&sig=ACfU3U2HOLB78XHl2o3q-JanapzSK-McJA&hl=bg&sa=X&ved=2ahUKEwjDpp2-zZXhAhWT5OAKHUfuBzUQ6AEwBHoECAkQAQ#v=onepage&q=%22electrochemical%20equivalent%20of%20hydrogen%22&f=false
--------------------------
For your convenience I am giving below the text of the problem and its solution.
--------------------------
12.97. In the electrolysis of sulphuric acid solution, 100 mg of hydrogen is liberated in a period of 20 minutes. The resistance of the electrolyte is 0.5 Ohm. Calculate the power consumed. Electrochemical equivalent of hydrogen is 1.044 x 10 -8 kg/C.
SOLUTION.
Prof. S. L. Srivastava's solution is given below.
Prof. S. L. Srivastava's solution consists of two lines only.
LINE 1. Current through the electrolyte is given by I = (m)/(Z x t).
LINE 2. Power consumed = (I) x (I) x (R) =  ((m)/(Z x t)) x ((m)/(Z x t)) x (R) = 31.86 W.
---------------------------
Prof. S. L. Srivastava stops here his calculations.
(The related solution's set of equations is not given here in order to save time and space. This set of equations however can be found in the book or in the link above.)
--------------------------
WE DEVELOPED FURTHER PROF. SRIVASTAVA'S SOLVED PROBLEM IN A NON-STANDARD MANNER.
OUR FURTHER DEVELOPMENT OF PROF. SRIVASTAVA'S SOLVED PROBLEM LED TO COP > 1.
HERE IS THE ESSENCE OF OUR APPROACH.
--------------------------
1) Let us calculate the inlet energy, that is, inlet energy = (31.86 W) x (1200 s) = 38232 Ws = 38232 J.
2) The Joule's heat, generated in the process of electrolysis is given by
Q = (I) x (I) x (R) x (t) =  ((m)/(Z x t)) x ((m)/(Z x t)) x (R) x (t) = (31.86 W) x (1200 s) = 38232 Ws = 38232 J = outlet energy 1.
3) HHV of hydrogen is 142 000 000 J/kg. Therefore the heat H, generated by burning/exploding of 0.0001 kg of hydrogen, is given by
H = (HHV) x (m) = (142 000 000) x (0.0001) = 14200 J = outlet energy 2,
where
m = mass of the released hydrogen
HHV = higher heating value oh hydrogen
4) Therefore we can write down the equalities:
4A) outlet energy 1 + outlet energy 2 = 38232 J + 14200 J = 52432 J
4B) inlet energy = 38232 J.
5) Therefore COP is given by
COP = 52432 J/38232 J = 1.37 <=> COP = 1.37 <=> COP > 1.
------------------------------
IMPORTANT NOTE. Constant pure water and cooling agent supply could keep constant the electrolyte's temperature, heat exchange, mass and ohmic resistance, respectively. Besides 0.0001 kg of hydrogen (and the related amount of the already split pure water) is small enough and can be neglected as a factor influencing the electrolyte's temperature, mass and ohmic resisitance.
-----------------------------
And one more interesting fact.
Literally the same solved problem can be found in an old Russian (still from the Soviet times) book "Сборник задач и вопросов по физике", 1986, p. 130, solved example problem 71. The authors of this book are Р. А. Гладкова and Н. И. Кутиловская. In the Russian version the data is a little different, that is, time is 25 minutes, the amount of generated hydrogen is 150 mg, Ohmic resisitance is 0.4 Ohm and the calculated power is 37 W.
Russians also stopped their calculations at 37 W.
Our further development of the Russian version led to the same COP = 1.37, that is, we have again the same COP > 1.
-----------------------------
IMPORTANT NOTE. The text above must be evaluated (SOLELY AND ONLY!) by highly qualified experts (Ph.D.) in electric engineering. Otherwise nothing will come out of it.
-----------------------------
Looking forward to your comments.