Premise of 20.5 m Pendulum-Length ( center of mass ) is not correct. According to my calculation center of mass is at 20.58 m


When the top of the 1 m rod hits the pin the rim-velocity ( at 20.58 m radius)  of the center of mass stays the same at the moment of impact.
The angular velocity of the 20.58 m long pendulum however is suddenly increased at the time of impact because angular momentum must be conserved  as the radius of rotation is reduced by 20 meters


Shortly after impact however deceleration of the center of mass takes place as it climbs up against 9.81 m/s² gravitational acceleration ( better deceleration) until all momentum is compensated.
I dont do the math but it might happen that the short pendulum loops past the top position ( at 12 o 'clock ) ccw-wise and then the behaviour is not
predictable .
I do not see any gain here...standart phisics...the plus-element of the Cyl & spheres experiment is missing


Mike

Well; do the math, angular momentum, cannot remain the same if the velocity of the center of mass remains the same. The velocity of the downswing tells us all we need to know.

The energy cannot remain the same either.  What you wish to happen simply doesn't. We are not talking about the 'cylinder and sphere' we are proving that energy can be made in the lab.

Would you like to show your math for the 20.58? 

The center of mass is 20 cm from the 5 kg and 50 cm from the 2 kg. The 5 kg is 30 cm from the point of rotation which leaves the center of mass at 50 cm from the pin.

Angular momentum is linear velocity time radius. When the radius is changed from 20.5 m to .5 m, and linear velocity remains the same (as you state) then angular momentum cannot remain the same.

A mass moving 1 m/sec can only rise .051 meters. So we can identify the original velocity.

The momentum is not (compensated ); it come back every swing.

You keep pretending that energy is conserved, but it never is. Only when no experiment is conducted or with magic friends; is energy conserved. 

your quote

QuoteWhen the radius is changed from 20.5 m to .5 m, and linear velocity remains the same (as you state) then angular momentum cannot remain the same.

Quote


increased angular momentum is caused by increased angular velocity ( mass is unchanged)


thats what I said:


my quote

QuoteThe angular velocity of the 20.58 m long pendulum however is suddenly increased at the time of impact because angular momentum must be conserved  as the radius of rotation is reduced by 20 meters"[/size]

Quote


I am sorry for not showing my math...as I have a very serious flue and my eyes are very much affected.
Promise, I will first recheck it and then post it later


https://www.youtube.com/watch?v=M6PuutIm5h4


since the value of the moment of inertia is smaller ( arms tight to the body) , the angular velocity increases and thus the value of angular momentum
stays the same.

QuoteYou keep pretending that energy is conserved

Quote


No, I just can not see it in this setup. The total moving mass of the guy sitting on the chair does not change and his main body-structure
still co-rotates with his arms and hammers


There is no full momentum-transfer from the big to the small masses as in the cyl and the spheres ( this is crucial !!! ). In the cyl and the spheres you need to step in at maximum speed of the small mass and seperate it when the big mass stops. If you dont do this the momentum flips back and forth between the big and the small mass until friction brings it to and end- momentum is used up - Your movies show this


Mike

Look it up; it is not angular velocity it is linear velocity; you can't make up your own formula.

People in spinning chairs are not experiments; you have no idea of the distribution of mass.

https://www.youtube.com/watch?v=sptVeNr_MpQ


Yes, when the spheres secure all the motion from the cylinder they must be released. 

The center of mass between 5 kg and 2 kg: separated by 70 cm; is 20 cm from the 5 kg, and 50 cm from the 2 kg. Not 28 cm from the 5 kg.