a good example of how easy it is to mislead the average person. The main thing is that no louse will sue.

https://www.youtube.com/watch?v=QRH8ksmRCuU


So let's do a little math! We'll calculate in RMS values 1/√2 = 0.7 (cosφ -0.77 indicated on the motor). Three-phase motor connection in delta, so for one phase.

The guy writes 10 kW: this is for 230V = 10000W/230V=43,48A.
 
Determine the resistance of the winding phase (total), the motor indicates 3.6A at a power of 0.75kW: R = U/I = 63.8Ω;

divide the value conditionally into active and reactive resistance equally (although this is incorrect): r0 = 63.8Ω * 0.5 = 31.9Ω

Next, calculate the index of the complete circuit, to begin with, calculate the load resistance of 10 kW: R(LOAD) = U/I = 230V/43.48A = 5.2Ω.

Let's calculate the current of the complete phase circuit with load I = U/(R(LOAD)+r0) = 230V /( 5.2Ω + 31.9Ω) = 6.2A

The first calculation shows that fig what there will come out at 10 kW, this is without taking into account the cross-section of the conductor on the current carrying capacity.

To get the desired current we need a function of the EMF drop, let's find how much we need to add:

Ui = I((R(LOAD)+r0) = 43.48A*( 5.2Ω + 31.9Ω) = 1612.74 V; the total EMF will be E = U+Ui = 230V+ 1612.74 V = 1842.74V.

For a complete circuit: I = (E-U) / (R(LOAD)+r0) = (1842.74V-230V) / ( 5.2Ω + 31.9Ω) = 43.48A For a section of circuitI = U/R = 230V/5.289Ω = 43.4A

That's all you can see from this show clip.   

Learn physics and master the solution of problems in physics. Without mathematical analysis you will remain losers.

Quote from: TommeyReed on July 31, 2023, 06:50:01 AM
Snake oil salesman are on this forum, be warned!

Clearly there are investors on this forum pushing this Holcomb device, I would caution anyone putting money down on these unproven claims.

Again, nobody has a single unit that worked or still waiting on their delivery after spending 50k+.

There's a old say, " If you can't sell it to the public because it doesn't work, try to sell it to a few people with a investment return and add more snake oil to the claims". Sounds like a Dennis Lee presentation on these forums.

SL clearly sounds like the salesman, yet he has more snake oil rubbed on his hands like a car salesman waiting for a payoff. At least a Salesman has a car you can test drive, SL has nothing!

Where is the real deal Mr salesman?

I see picture, meters and claims; but no physical machine.

It's unlikely for people on this forum to not show a prototype of how something should work, Yet Mr salesman is not doing that. WHY not?

SL need to come out of the closet and explain whats in it for himself, because he clearly has nothing to show but claims of someone who can't prove free energy.

SL sounds like someone who invested a lot of $$$ on this fantasy free energy machine.

Mr Salesman, you need to explain your behavior!

Tom

Tommey,

If, in fact, you did get taken for $50K (through your own stupididy, or not) we might be able to
recover a good portion of that $50K back to you:

A very remote associate I know is pretty good at "recovery" - of course he has a fee but it beats 
a "poke in the eye with a sharp stick" and he does present legal, and other methods, as required. 

Let me know if you need help - get a TACP and RM the #. 

Just trying to help "clear the air" here - nobody deserves to be cheated, no matter how stupid they
are!   I've been there and done that...

SL

Quote from: rakarskiy on August 01, 2023, 12:49:48 AM
a good example of how easy it is to mislead the average person. The main thing is that no louse will sue.

https://www.youtube.com/watch?v=QRH8ksmRCuU


So let's do a little math! We'll calculate in RMS values 1/√2 = 0.7 (cosφ -0.77 indicated on the motor). Three-phase motor connection in delta, so for one phase.

The guy writes 10 kW: this is for 230V = 10000W/230V=43,48A.
 
Determine the resistance of the winding phase (total), the motor indicates 3.6A at a power of 0.75kW: R = U/I = 63.8Ω;

divide the value conditionally into active and reactive resistance equally (although this is incorrect): r0 = 63.8Ω * 0.5 = 31.9Ω

Next, calculate the index of the complete circuit, to begin with, calculate the load resistance of 10 kW: R(LOAD) = U/I = 230V/43.48A = 5.2Ω.

Let's calculate the current of the complete phase circuit with load I = U/(R(LOAD)+r0) = 230V /( 5.2Ω + 31.9Ω) = 6.2A

The first calculation shows that fig what there will come out at 10 kW, this is without taking into account the cross-section of the conductor on the current carrying capacity.

To get the desired current we need a function of the EMF drop, let's find how much we need to add:

Ui = I((R(LOAD)+r0) = 43.48A*( 5.2Ω + 31.9Ω) = 1612.74 V; the total EMF will be E = U+Ui = 230V+ 1612.74 V = 1842.74V.

For a complete circuit: I = (E-U) / (R(LOAD)+r0) = (1842.74V-230V) / ( 5.2Ω + 31.9Ω) = 43.48A For a section of circuitI = U/R = 230V/5.289Ω = 43.4A

That's all you can see from this show clip.   

Learn physics and master the solution of problems in physics. Without mathematical analysis you will remain losers.

Or simply use an on-line calculator.

Quote from: SolarLab on July 30, 2023, 04:40:31 PM


Was this the video "where it doesn't appear the meters are properly connected":

Gene testimonial video:

https://vimeo.com/user81692192

Maybe you could point out exactly where the error is!

Thanks in advance...



SL

SL,

Just noticed something about this video. Please confirm the system voltage.
Thanks.
bi

Quote from: bistander on August 01, 2023, 03:31:36 AM
Or simply use an on-line calculator.

This is only if you know the essence and you need to reduce the time. But in any case the phase resistance cannot be the same for 10 kW and for 0.75 kW. By the way, in reality things are even sadder.