@All,

Good morning. My circuit has run through the night. The battery voltage has CLIMED a tiny bit
since yesterday. It is now 0,588 Volt over the battery. I will let the circuit run through the day.
It will be fun to see how long this circuit can run on that single battery before the LED stop lighting.

This is really amazing!

Groundloop.

@ All:

One of my Stubblefield earth battery bifilar coils puts out over 30mA by itself, not even in the ground yet, just a little wet.  I'll bet it would replace the AA battery in your circuits.  If I can, I will give it a try.  These are bifilar coils with an iron core and cotton insulation between the iron core, iron wire, and copper wire. (all the wire is bare)  When in the ground they should put out power forever.  This should be interesting.

Bill

@groundloop

After you get conclusion on your's circuit, please follow the ratio of bifilar coil. You will see different.

@bill

as my friend said, if we can harmonize/tuned oscilation with earth it will puts out / pull "something". Range of harmonize/tunning area of earth betweeen 30 Khz --- 350 Khz.
Where he get that number, he never told me.


zon

@Bill,

It will be more intresting if this circuit as it is now turns out to be running an "impossible" long
time from a depleted NiMeh battery. The LED is bright enough to actually read a book in total
darkness. (Yes, I have tested that.)

Now a "far out" theory:

The fully depleted NiMeh battery (less than 0,590 Volt) is now performing as a high value capacitor.
Because the circuit loads the battery and the battery can not and will not provide any charge then
the active environment is putting in the energy needed to keep the oscillator going. The battery is just like a spring, we try to stretch that spring even further to get our energy to the circuit, but the battery can not
do that anymore because it is empty, so the energy must be taken from somewhere else. Thus, we have created a negative resistor inside the battery.



Another theory is the way this circuit works. The three diodes and the output coil makes a loop of current circulating one way only. The oscillator keeps that loop running at each pulse. Because the speed of the circulating current is very high the extra energy is coupled back to the driving coil and thus charge the battery.

Just some thoughts................

Groundloop.

@ Groundloop:

You don't think the same principle would apply when using a Stubblefield bifilar coil in the ground?  I see what you are saying about what you think the "dead" battery is doing and I don't/can't disagree as I am still limited in my knowledge of electronics.  I think it might be possible that the cell in the ground might just have the same reaction as the AA battery.  Maybe not.  So many experiments to do, so little time.

Bill