808 G6 OSIRIS ENERGY TECHNOLOGY

[luishan]

I think I am stupid. I still not understand the concept.
Would you show us schematic and would you explain that ?
Also Would show us on Youtube the working video ?
Thank you.

[e2matrix]

I think that's how I remember learning it also - what GL said. 
   So osiris I'm not sure I understand exactly how or what you are doing with this setup but it sounds like you may be switching some very high current.  If that's correct what will you be using for the actual switching where contact is made and broken with that much current? 
    Nice battery finds - wish I had that much battery power here but can't afford that kind.  Still looking for a deal on a forklift battery though...

[nievesoliveras]

Thank you @groundloop!

I will recheck my information sources when I get the time to clarify for my peace of mind about the voltage and capacitance on a capacitor when in series or parallel.

The document you posted says that I am wrong.

I need to know now where I learnt that wrong information.

Jesus

Edit:

Looking for the information I found this from goldmine that corroborates your words.
The two capacitors in series add the voltage but cut the capacitance in half.
The two capacitors in parallel add the capacitance and the voltage stays the same.

[nievesoliveras]

So according to the new information it should be like this:

[TinselKoala]

The problem seems to be a misunderstanding about the meaning of the voltage rating of a capacitor. It's NOT like a battery's rating !!

The voltage rating of a cap is the maximum safe voltage you can put on the cap without taking the chance of "puncturing" or shorting the dielectric between the capacitor's electrodes.

So putting caps in series logically adds together their voltage ratings--just like stacking a bunch of insulators adds up the total voltage that can be stood off by the stack.

The ENERGY on a capacitor is proportional to the SQUARE of the voltage that the cap is charged to, but is only linearly proportional to the capacitance. Energy (in Joules) = (C*V*V)/2, with capacitance in Farads and volts in volts. The power able to be delivered by a capacitor depends on how fast the charge energy can be released into an external circuit and is complicated.

The capacitance of a cap can be considered a constant. The energy on the cap is proportional to the square of the voltage and can be thought of as the energy it takes to stuff a bunch of mutually-repelling charge carriers into a tiny space--the more charge, the greater the energy required, and the more voltage (pressure!). The tighter the space, the more energy required...or the more the charge, the more energy required....and so on.