Homopolar torqueless gear generator.

[exnihiloest]

"In generator mode, the Lorentz force F=q*v.B makes the electrons flowing radially."

Just a question/statement.  Could this step be viewed as:  The shortest (lowest resistance path) on the spinning disk/magnet is from the center of the disk to the outside.  This "path" creates a wire on the disk in essence that passes through the magnetic field, which collects a charge and also creates an electron path for power to flow when a load is applied.

I agree.

It appears that the magnetic field has the effect of suspending the charge on the area of the disk, avoiding discharge through the disk, rather preferring the low resistance path of the "wire" to the load.
Liberty

Liberty, I'm not sure to understand exactly what you say. So if my reply is not clear relative to your remark, please let me know.
The Lorentz force applying onto the electrons is always directed perpendicularly to their speed.
When the circuit is open, the electrons tend to accumulate toward the disk rim until the Coulomb force due to the field gradient inside the disk (because of the electrons displacement), balances the Lorentz force.
When an external circuit is connecting the center of the disk to a sliding contact on the rim, the force on the electrons is still acting only radially. The electrons are still pushed to the rim, but they can now travel toward the external circuit when they pass near the sliding contact. Therefore from a macroscopic sight, the current can only be viewed as flowing through a virtual wire between the center and the sliding contact.

[exnihiloest]

What part of "ignore this thread" didn't you understand.

I'm in a hurry to see videos of your self-rotating double Faraday's disk.
Permit me to thank you in the name of the mankind for your great invention!

[exnihiloest]

...This radial force translate into a voltage in an ohmic circuit.
...

It is false when the external circuit is not connected.

You forgot that the Coulomb force inside the disk balances the Lorentz force after the initial charge displacement toward the rim.
It is only the external circuit that breaks this balance, allowing a current to flow.

If you put a voltmeter connecting the center of the disk to the rim, and rotating with the disk, you will observe no voltage (well known result of experiments).

[broli]

It is false when the external circuit is not connected.

You forgot that the Coulomb force inside the disk balances the Lorentz force after the initial charge displacement toward the rim.
It is only the external circuit that breaks this balance, allowing a current to flow.

If you put a voltmeter connecting the center of the disk to the rim, and rotating with the disk, you will observe no voltage (well known result of experiments).

You're so over the place it's sad. There's nothing wrong in what I said. In fact you are just arguing for the sake of arguing.  I'm saying 1+1=2, you are repeating "wrong, it should be 1+1=2" which leaves me questioning your presence here. I'll repeat, IGNORE THIS THREAD.

[Liberty]

I agree.

Liberty, I'm not sure to understand exactly what you say. So if my reply is not clear relative to your remark, please let me know.
The Lorentz force applying onto the electrons is always directed perpendicularly to their speed.
When the circuit is open, the electrons tend to accumulate toward the disk rim until the Coulomb force due to the field gradient inside the disk (because of the electrons displacement), balances the Lorentz force.
When an external circuit is connecting the center of the disk to a sliding contact on the rim, the force on the electrons is still acting only radially. The electrons are still pushed to the rim, but they can now travel toward the external circuit when they pass near the sliding contact. Therefore from a macroscopic sight, the current can only be viewed as flowing through a virtual wire between the center and the sliding contact.

I understand what you are saying.  But I am not convinced that the "Lorentz Force" actually exists.  The physics experiments show a wire hanging in between two magnetic poles.  And when a current is applied, the wire will swing in one direction or the other depending on the direction of current flow through the wire.  However, the wire can escape in it's travel to a place of less magnetic field in these experiments. (Indicating that the wire may just be propelled from or to a magnetic pole.  If you take a magnet in between the two poles, it only reacts with the field of the magnet and does not push off of the flux lines.  To truly make this test valid, (proving the force is on the charged particle) the wire would have to be suspended in between two magnetic poles in attract, where the wire can not escape to a place of less magnetic field, to prove that the current flow in a wire will repel or attract off of flux lines only and not just the spherical magnetic poles of the two magnets in attract.  Perhaps this has already been done?  I just haven't seen it. 
Additionally, if the Lorentz force is actual, you should be able to take two ring magnets in attract and place a current carrying wire in between them and propel off of the flux lines to make a motor.  I don't think that this will work, but I might be wrong.  Perhaps a motor has been made like this?

It seems to me that on the homopolar disk, that no voltage is being generated unless the contact is made on the disk to create the virtual wire.  Because when the virtual wire is created by making a contact with a load, then this wire is crossing magnetic lines of flux, due to the spinning disk, and then generating an electrical potential which flows out to the load.  When no connection is made, there is no voltage being produced on the spinning disk. 

Just something to think about??