Submersible Engine Design

[TommeyLReed]

This is another project I'm working on, is using displacement of water to convert it into direct rotational energy.
I should have a prototype done soon.

What do you think?

http://www.youtube.com/watch?v=AnraqeoGaNU

http://overunitynow.com/page26

Tommey Reed

[exnihiloest]

This is another project I'm working on, is using displacement of water to convert it into direct rotational energy.
I should have a prototype done soon.

What do you think?

http://www.youtube.com/watch?v=AnraqeoGaNU

http://overunitynow.com/page26

Tommey Reed

When you provide air to a cone at the bottom, you replace a certain water volume with air. As water is incompressible, this air volume can be made only by raising the water above, what is strictly equivalent to raise to the surface the same volume of water as the volume of air in the cone. Work is v*d*g*h where v is the air volume in a cone at the bottom, d the water volumetric mass, and h the height.
It follows that the work needed to compress air in order to fill a cone is exactly what the system will provide back when the cone will rise up, restoring towards the bottom the volume of water that had been displaced upwards.
No extra energy. Buoyancy and Archimedes principle is a well known phenomenon.

[quarktoo]

As the air rises, it expands and displaces more water assuming you did not fill the cup all the way.

Does a cubic foot of displacement have the same amount of buoyancy 100 feet below the surface as it does just below the surface? Yes because the water is incompressible.

So the energy you gain is due to expansion of the water as the cup rises. The taller the bucket line the more efficient it gets.

Sound about right?

[tbird]

Tommey Reed,

i think you have overlooked something.  436.96 lb of upward force sounds like a lot, but you should look closer.

let's say the compressor is a simple box, 1 foot x 1 foot x 1 foot (1 cubic foot).  the top is moveable and when weight is added to the top, it would go inside compressing the air.  to get your 4.4 psi (pounds per square inch), you would need 144 (1 sq ft) x 4.4 = 633.6 lbs.  of course the volume inside will be reduced also.  this sounds like a bit more than your 436.96 you predict.

maybe you should have another look at this.

tom

[TommeyLReed]

My data say that 4.4(salt water), psi is needed to force air under water at a depth of 10ft. fill the cube (12^3) 1728 cu/in having a displacement of 1cu/ft of are. This will produce at a 10ft lift:(62.3*10)=623lb
pressure ((4.4 psi x 1728)/12)=633.6lb is what I get.
Now as you may know to compress air at a rate of 3cfm@90 psi=about 1hp, this could also much more volume at (90psi/18)=5 psi@(3*18)=54cfm.
Would not a 1hp make a total of 54cfm@5psi?

If 6.28 cu/ft in needed to turn a 2' wheel to turn 1 revolution, this will have a constant load of 62.3lb*10ft=623ft/lb.
At 60 rpm's or 376.8 cu/ft of air is need to make ((623*60)/5252)=7.12hp
If 7.11hp is used to pump the air pressure is it takes 1hp for each 54cfm@5 psi. Would this not also say that 7.11*54cfm=384.3?
384.3/376.8=1.02,102% efficient?
I do know that the less psi to compress, the more efficient the pump can be...