Rosemary Ainslie circuit demonstration on Saturday March 12th 2011

[poynt99]

I had posted this in February. Maybe it's not what you had in mind.

.99

[nul-points]

Hi again nul-points.  You've sort of put two batteries in series.   And then given two loads with two switches.  Is that all I've managed in that design?  LOL.  If so, let me try this again.  I'll get back here when I've redrawn it.
...
Rosie

hi Rosemary

yes, that's effectively what you drew above:
(hence my comment that your circuit may not operate as you expect)

    two cells in series, two resistors in series, two switches in series

it doesn't matter what order these occur in the ring circuit
(the diodes across the switches always need to have the same polarity sense, of course)

you also indicated that you were looking for a solid-state solution - hence no relays in the equivalent circuit i posted

no worries

all the best
np


http://docsfreelunch.blogspot.com

[Rosemary Ainslie]

Poynty - I'm not sure if that cuts it.  I'll need to print it out.  Can't quite read it off the computer.  Unless you can do it a tad smaller.  But I should be able to get it printed today.  Meanwhile here's another shot at showing what I'm trying to get to. 

Sorry about the smudges.  I think this may just work with reed switchings and switching in antiphase.  Anyway - it's what I'm trying to point to.  Just think of the current switching around the middle like two inverted 's's or alternatively think of a swastika going first one way and the then the other. 

Sorry about the smudges.  Not the best drawing in the world.

Kindest regards,
Rosemary

[Rosemary Ainslie]

Sorry about that drawing.  Golly.  It's now got HUGE.  And it's so smudged. 

Anyway.  Here's what I'm trying to do.  The positive current from either battery always first feeds into the positive terminal of the other then finds it way back to the negative terminal of the source.  Then the negatively induced current during the 'off time' first gets routed to the negative terminal of the other battery before it returns to the positive terminal. 

That way - as I see it - every 'on' will result in a recharge as will every 'off'.   I'm open to correction here.  And I have no idea if it's even feasible.  It's just a principle that haunts me.  It seems to answer that closed system that you all look for.  I'm entirely satisfied that it will do no more nor less than our own circuit.  But it answers the logic better.  And then, only if it's doable at all.

Anyway.  I'll await comments and see if I can wrap my head around Poynty's design.  Thanks for that.

Kindest regards,
Rosie

Poynty - please get those fatuous and entirely erroneous comments of FuzzyTomCat off that thread.  It's already been polluted out of mind.

Thanks
R

[nul-points]

Here's what I'm trying to do.  The positive current from either battery always first feeds into the positive terminal of the other then finds it way back to the negative terminal of the source.  Then the negatively induced current during the 'off time' first gets routed to the negative terminal of the other battery before it returns to the positive terminal. 

That way - as I see it - every 'on' will result in a recharge as will every 'off'.   I'm open to correction here.  And I have no idea if it's even feasible.  It's just a principle that haunts me.  It seems to answer that closed system that you all look for.  I'm entirely satisfied that it will do no more nor less than our own circuit.  But it answers the logic better.
...
Rosie

ah Rosemary - your previous circuit was better!  ;o)


i believe that you have a clear goal in mind - but unfortunately not a clear path ahead as to how it might be achieved

current will flow through a circuit path only when there is a net potential difference applied across it


as an exercise in becoming more familiar with circuit design, i can recommend a next step for you, after an initial sketch attempt at expressing a new idea:

consider each source of energy in turn, and, with a few helpful example component values to make the maths go more smoothly, get a feel for the main current paths, values, and hence voltage drops around the various series & parallel paths between the +ve & -ve of that supply

this approach will help you develop a better 'feel' for how the various circuit elements are likely to work together - and hopefully save you wasting too much effort on the non-viable circuit ideas

all the best
np


http://docsfreelunch.blogspot.com