PhysicsProf Steven E. Jones circuit shows 8x overunity ?

[Omega_0]

Prof Jones,

You are indeed doing a work of great value and I respect your open-mindedness and understanding. I hope something interesting will come out of this circuit.

If you seriously consider heat measurements then you will need a high end calorimeter. It needs to be scaled up into watts range to be above error margins. The heat is not much in this version but the good thing with calorimetry is that you can leave it running for hours and have a cumulative effect. It is the final measurement for any OU setup.

I have another suggestions regarding measuring spiked AC besides the rectifier/filter method. There are true RMS meters that measure the true RMS voltages and are independent of waveform. (There is a very fine and accurate resistance inside them which heats up and its temperature is directly mapped into volts).

http://en.wikipedia.org/wiki/True_RMS_converter

PS: I have no idea about their bandwidth ratings

[Pirate88179]

Dr. Jones:

I am watching your experiments and can't wait to see what happens next.  Best of luck to you sir.

Bill

[JouleSeeker]

Prof Jones,

You are indeed doing a work of great value and I respect your open-mindedness and understanding. I hope something interesting will come out of this circuit.

If you seriously consider heat measurements then you will need a high end calorimeter. It needs to be scaled up into watts range to be above error margins. The heat is not much in this version but the good thing with calorimetry is that you can leave it running for hours and have a cumulative effect. It is the final measurement for any OU setup.
...

  Hmmm...  I may have access to a high-end calorimeter.  But I'm trying to figure out just how one would use it.  Perhaps put the entire device in the calorimeter -- except for the output leg of the circuit (Diode + resistor Ro).  The CSR resistors are superfluous in this measurement method and are removed.   Measure the heat-rise for this "input" portion of the DUT as total Pin, using the calorimeter.  Then place the isolated output leg of the device in the calorimeter and measure the heat-rise separately, as total Pout.

Does this make sense?  I'm wondering where to put the toroid itself, in the input or output leg?  Perhaps that won't make much difference...

Thanks for the encouragement, also @Pirate.

[DrStiffler]

With the potential of 900mW as stated in the PW article, I see no reason why a high end calorimeter would be required, although one used in bio work would dispel any negative feed back on the quality and accuracy. Again if capable of 900mW it can be done with a home build unit, foam and 10 to 20mL of water and a good indicator. Of course you need to setup a calibration protocol.

As far as what to put in the unit here IMHO are the possibilities. 1)Entire unit exclusive of the 1ohms unit in series with your power rail. Under this condition a number of possible results can be seen; a) The heat in the unit is below what the input measurement shows should be present, this would indicate one or more components are cooling, most likely the transistor as this is the most probable source. b) The heat indicated is above what is shown to be the input. c) The input and output are for all practical purpose equal (~100% eff.).
2) If cooling is seen a tedious protocol of component isolation is then presented and would take considerable work and circuit/component splitting to arrive at an answer. 3) The unit presents heat above input, this would be the most desirable and I'm sure you understand why.

Unless you want to keep the forums busy and people trying replications that do not have the required test equipment I might suggest this would be a great idea to find a calorimeter. Once you are assured of you digital reading as compared to the actual heat measurement them replicators can have a base line to work from.

[JouleSeeker]

Good to hear from you, Dr. Stiffler. 

Unless you want to keep the forums busy and people trying replications that do not have the required test equipment I might suggest this would be a great idea to find a calorimeter.

OK -- more pondering.  The simplest experimental test I can think of using a calorimeter -- place the ENTIRE circuit in a calorimeter with the only source of energy being a capacitor (say 10F) in place of the battery.  The available energy Ein is known from Ein = 1/2 CV**2.  Then turn the device on (inside the calorimeter) and let it run.  Calculate the total energy OUTPUT Eout using the calorimeter.

n = Eout / Ein.