PhysicsProf Steven E. Jones circuit shows 8x overunity ?

[xee2]

The question is, how is the change in magnetic field at the center of the loop SENSED by the loop, when the magnetic field outside the toroid itself is ZERO?    There is no magnetic field to affect the electrons in the wire, from the toroid, just an electric field.  And does this electric field propagate outward from the toroid at the speed of light?  I suppose so.

Sorry, I do not think I answered this question with my previous post. Sometimes it takes a while to sink in.

Each loop is coupled to the toroid core as a result of charges in loop (moving electrons) causing magnetic field in core. This coupling is bi-directional. If the loop current can effect the core, then the core can effect the loop current. The coulpling is between to the moving charges (electrons) in the loop and the moving charges (electrons) in the core domain atoms. I do not think that the coupling can be explained with classical "Faraday/Maxwell" concept of magnetic fields. I think it requires a relativistic solution for electric fields of moving charges. I think the best classical solution is to compute the current induced in loop from the change in flux through the center of the loop. I hope that is a better answer.

[nul-points]

 

[...]
Frankly, I don't give a damn.

i don't give a damn either, frankly


if you have something to share, do it and cut the cr&p


if you just want to groom a bunch of acolytes you can patronise, then go start your own thread

[poynt99]

@ frankly,

I have already provided the answer to the question regarding how current is induced in a loop of wire outside of either a solenoid or toroid. It's the electric field.

Now, regarding your initial question about what causes a magnetic B field:

The electron has charge. A spinning charged particle has a magnetic moment, i.e. it is a magnetic dipole. There are many free electrons in copper. When an electric field is applied to a copper wire, the magnetic moments of these free electrons become aligned such that a net magnetic moment (or field) is created which encircles the wire.

.99

[dimbulb]

Frankly
I see your frustration on the many aspects of the tesla magnifier,
I can tell that the rant is really a caring one and not giving up.
Your focus on battery as a  negative resistor function is good priority.
The math aspect in this regard is working within the negative resistance zone.
The battery impedance shifts and needs tuning until stablized.

As you know the tesla constraints on voltage are often extreme to most.
I don't know what Nickola had exactly in every part of his system.

I have heard that when tuning at minimum he would look for faint corona discharge
that was hard to see except under low light.

I used 11 turns for L2 and it was inline with L1 tightly wound no gaps except
between L2 and L1 was approx 3/32 to 3/8 inch. this was my finese adjustment.

[frankly]

@ frankly,

I have already provided the answer to the question regarding how current is induced in a loop of wire outside of either a solenoid or toroid. It's the electric field.

Now, regarding your initial question about what causes a magnetic B field:

The electron has charge. A spinning charged particle has a magnetic moment, i.e. it is a magnetic dipole. There are many free electrons in copper. When an electric field is applied to a copper wire, the magnetic moments of these free electrons become aligned such that a net magnetic moment (or field) is created which encircles the wire.

.99

Excellent, now we are getting somewhere.

So, could the amount of these dipoles in the wire, all lining up in one direction, have anything to do with the capacity of the wire? So, if long, or in a coil, deliver a pulse of energy to a load? In other words....is that what amperage is? The amount of dipoles aligned and then relaxing? Is that what the term reluctance equates to? The dipoles' relaxation speed?

SO.

Resistance then, must be related to the SIZE of the dipole. It's mass. So, aluminium, a lighter substance and yet, a metal and a conductor, conveys energy far easier for less space, the dipole's are smaller.

Cool. I hope you see the correlations here, because it is important to understand this simple stuff.

So, if the dipole, being aligned, and then allowed to relax, delivers that inertia to another component, called a load, or in the case of DC energy, has to be pulsed, (except with a resistance like light bulb, which is itself a resonating element), why does it have to stop spinning? Why not simply, instead of aligning the dipoles in the wire, and then allowing them to relax, set them spinning?

This, then, is also a changing magnetic field, so, delivers energy to the load just the same.

It is just that, one must use OSCILLATING DC energy to achieve this rotation of the dipoles.

If you investigate the actions of the elements in the present circuit, I think you will find, once the calculations are done, that the "sweet spots" described, are where the capacitance and inductance match harmonically, so, some extra rotation of the core's dipoles is occurring.

Also, the "feedback loop" is simply where this opposite polarity energy is coming from to achieve this.

Tesla was using OSCILLATING DC of HIGH FREQUENCY and HIGH POTENTIAL.