Background discussion of TT`s Pyramid

[fritz]

... recently, I did some recherche on  leylines and earth radiation.
I found lots of references of people claiming that groundwater moderates neutron radiation from the partly radioactive earth core.
Under normal circumstances that fast accelerated neutrons/ radiation should rise very fast without ionization. If the radiation passes certain materials, like water for example, some moderation takes place and the chance for an early decay and the emission of ionizing radiation increases.

Well, googling for "neutron detectors", especially "selfpowered neutron detectors" - I found lots of things similar to TTs reactor. (without a pyramide of course).

copper tubes  can be used as waveguides for ultracold neutron radiation.
If well polished - they can operate as perfect mirror.
This would be a reason why copper reductions top/bottom don´t work.
There are coaxial copper tubes, partly filled with quartz and sometimes with added water...
Other detectors have an inner coil - where the length, diameter, material of that inner wire has to be tuned for the the wavelength of that emission.
The output of such detectors is _DC_.

Other detector used doped Gypsum (Caso4) as detector

... just for reference.

[neptune]

For those who are still worried about the absolute dimensions of the pyramid . Go to the main thread , page 6 and find reply number 81 by Duff . Quoted in this reply is the original specification by TT . One very relevant fact is this . He says that if you measure from the top of the pyramid , down one of the diagonals to the Floor , it must be exactly 1 metre . If you used a rigid ruler to measure this , you would find that there would be a triangular gap between the ruler and the pyramid base frame at the bottom , because the base frame has vertical sides , 2 cms tall . Likewise , when you fit the plasterboard , there will be a triangular cavity between the board and the base frame . From all this I conclude that the 1 metre dimensions are the dimensions of the inside of the plasterboard shell . But if you measured the square made  on the floor by the plasterboard lower edges , it would be slightly more than 1 metre square . I hope this makes sense .

[k4zep]

... recently, I did some recherche on  leylines and earth radiation.
I found lots of references of people claiming that groundwater moderates neutron radiation from the partly radioactive earth core.
Under normal circumstances that fast accelerated neutrons/ radiation should rise very fast without ionization. If the radiation passes certain materials, like water for example, some moderation takes place and the chance for an early decay and the emission of ionizing radiation increases.

Well, googling for "neutron detectors", especially "selfpowered neutron detectors" - I found lots of things similar to TTs reactor. (without a pyramide of course).

copper tubes  can be used as waveguides for ultracold neutron radiation.
If well polished - they can operate as perfect mirror.
This would be a reason why copper reductions top/bottom don´t work.
There are coaxial copper tubes, partly filled with quartz and sometimes with added water...
Other detectors have an inner coil - where the length, diameter, material of that inner wire has to be tuned for the the wavelength of that emission.
The output of such detectors is _DC_.

Other detector used doped Gypsum (Caso4) as detector

... just for reference.

Good morning Fritz,

Searched as you mentioned, also searched and looked at articles on Piezoelectricity  and poling of material, my oh my there is some interesting material out there.  A lifetime of research can result if/when I get this Pyramid running!!!!!  Some very good clues as to how it works and where the energy is coming from.  But not theories now, just make the device work!!!!!

Respectfully
Ben K4ZEP

[NickZ]

  So,  a detector is taking in one type of radiation, and converting it to DC current.  What is the point of the conversion?  And how might that be similar to what the pyramid does, or what we are doing here. 
   Radiant Energy is  radiated, or is a type radiation, as it is radiated from its source.  Could that be what is being picked up by the pyramid?  Is there any correlation or not? 
  Also, if this type of radiation can be converted through a process to produce DC current, even without the use of the pyramid, the pyramid may not be even be needed, if this were true.

[gegyx]

@ Neptune
Maybe.
But without knowing the subtleties of the English language, I understand something else.

1- « Now you keep the square-tubes (2pc. with 1000mm) and give them to 2 opposite sides of the plate.
Cut 2 pc. of square-tubes to 960mm and give them to the plate to create a square.”

Ok, the base is a square, with 1 meter on the outside of the tubes ==> on my plan: 1 meter = b

2 - You say:
« One very relevant fact is this . He says that if you measure from the top of the pyramid , down one of the diagonals to the Floor , it must be exactly 1 metre . If you used a rigid ruler to measure this , you would find that there would be a triangular gap between the ruler and the pyramid base frame at the bottom , because the base frame has vertical sides , 2 cms tall . Likewise , when you fit the plasterboard , there will be a triangular cavity between the board and the base frame . From all this I conclude that the 1 metre dimensions are the dimensions of the inside of the plasterboard shell . But if you measured the square made  on the floor by the plasterboard lower edges , it would be slightly more than 1 metre square . I hope this makes sense .”

The problem is that TT speaks (on videos) of an equilateral triangle.

What makes sense to me, as you Neptune, is to consider the inside of the plaster.
==> on my plan: 1 meter = c + d


But Thomas said something else:
« Mark exatly 1000mm from the bottom of our Metalsquare (in the corners) to the 3/8" Tube and mark it from each Corner….

If you measure from the absolutely Bottom of the 20/20 ground-structure (without wood-plate) to the TOP, you have to measure exactly 100 cm. (on the Corners).”

So from the top corner of the square base to the apex.
==> on my plan: 1 meter = c
…And it is no longer an equilateral triangle ... 


But Duff also wrote:
“Thomas states: "we have to give away the 20mm of the groundframe". NOT CORRECT. The diagonal that runs out of that corner is 25mm wide (on edge) AND in order to make the weld on the bottom of the tubing you certainly have to give youself some space to work

I ask Thomas no less than 4 time for pictures of that joint and his final response to me was if I didn't know how to do it I should look at what others were doing. Well it had nothing to do with not knowing how to do it but rather his instruction made no sense.”