My Invention

[johnny874]

James,

I built a 2SO a few years ago and have been experimenting with it on and off ever since.  I have progressed to an overbalanced wheel that turns continuously in one direction, and have been testing various feedback mechanisms for that design.  Based on your drawings I think I can modify my original model to add in the lifting cord.  It is a basic wooden design with no bearings but it should suffice.  To get some quick feedback, I will physically attach the weight to the cord, because what you are really seeking (i think) is whether the balance weight will not only reset the main lever, but also raise the weight to it's original release height.  I will see what I can do this weekend (Aug 18 and 19) and will report back.

Rick

  Rick, Thanks.
Hopefully it won't take to much of a modification. I might make a basic set up to show a simple catch and release mechanism.
There is a way the 2SO might work based on what I've realized. The movements of the pendulums might need to be controlled
to realize the difference in force they both would have relative to the center of the cross beam.
Any more, I think just showing where something does work to shut up the critics might be what would make it worth while.

@TinselfKoala,
Wanted to go to school for electronics but something always happened to where I ended up with machining and mill wrighting.
it does take something to build. but like you probably know from your own work that it can be a headache trying to figure out how you want to set something up. And I did watch a few of the videos you have posted. 

                                                                                                                         Jim

[zoelra]

You have me thinking about the old design again.  In my designs I purposely placed the pendulum pivot point farther away from the lever pivot point than the balance weight (2:1 to be exact).  I did this to increase the range of motion of the pendulum pivot point so it would be easier to view and measure.  Capturing the pendulum bob in line with the main lever could be accomplished in many ways.  The first thing I will do is physically attach it to the lever (I have done this already) and show that the counter weight will easily lift the pendulum bob and reset the lever.  The additional feature you are suggesting (raising the weight back to it's original height) is the what is really in question.  I haven't done any math yet, but I would think that if the bob is close to the lever pivot point, there is a good chance, with the proper pulley ratio's, that the counter weight will be able to lift the bob back to it's original drop height.  Another thing to consider is releasing the weight near the 12 o'clock position (or at least somewhat higher than the 3 o'clock position).  This gives 4X CF at the bottom of the swing.  4X CF allows for a bob of less weight which will help when it needs to be lifted back to the reset position.   Also, the force required to raise the bob near the top of the swing is less than the force required to raise the bob when it is at the 3 o'clock position.  I'm sure you are already aware of these things but I thought I would mention them to be safe.

Rick

[johnny874]

  Rick,
one reason why I thought of placing the fulcrum the same distance from the pivot of the cross beam that the bob is from the pendulum is to keep tbe math basic.
If the lifting line on the counter weight side is furtber from the cross beam's pivot than where tbe lifting line is lifting the bob, it will lift it higher,
it's this increased lift that would allow for perpetuallity

    Jim

edited to add; when the bob is being lifted, it's angle to the fulcrum doesn't matter.
with something like a 30 degree angle, that might be the most efficient swing and would move the bob 1/2 the distane it is from it's fulcrum, what this does is allow for the opposing side to have sufficient lifting force and extra energy left over,
by having tbe lifting line attached to the cross beam on the cw side, it will have more movement tban the bob would when the cross beam tilts.

[johnny874]

You have me thinking about the old design again.  In my designs I purposely placed the pendulum pivot point farther away from the lever pivot point than the balance weight (2:1 to be exact).  I did this to increase the range of motion of the pendulum pivot point so it would be easier to view and measure.  Capturing the pendulum bob in line with the main lever could be accomplished in many ways.  The first thing I will do is physically attach it to the lever (I have done this already) and show that the counter weight will easily lift the pendulum bob and reset the lever.  The additional feature you are suggesting (raising the weight back to it's original height) is the what is really in question.  I haven't done any math yet, but I would think that if the bob is close to the lever pivot point, there is a good chance, with the proper pulley ratio's, that the counter weight will be able to lift the bob back to it's original drop height.  Another thing to consider is releasing the weight near the 12 o'clock position (or at least somewhat higher than the 3 o'clock position).  This gives 4X CF at the bottom of the swing.  4X CF allows for a bob of less weight which will help when it needs to be lifted back to the reset position.   Also, the force required to raise the bob near the top of the swing is less than the force required to raise the bob when it is at the 3 o'clock position.  I'm sure you are already aware of these things but I thought I would mention them to be safe.

Rick

  Rick,
Here is something you might want to consider for your 2SO. The bob's on both pendulums are connected much like a locomotive's wheel is connected to another one.
The trick if you will is to have the motion of the apparatus controlled at all times. When the pendulums swing from left to right, they do it only after the left side becomes lower than the right. This should give the right side maximum leveraged potential.
And when the right side drops lower, the bob's could then swing to the left. It may just be that when bob is in it's inner position. One way to try this before going into a build is to lock the pendulum's in the different positions that the attached diagrams reference and see if the proper movement is to be found. If so, then the hard work would begin and that would be figuring the way to make it work.
And if anyone is wondering, after 2so.4, 2so.1 follows in what would hopefully be a repetitive cycle.

                                                                                                                                         Jim

edited to correct spelling.

[zoelra]

Since both pendulums are tied together in a way that their positions along their respective paths would be the same (that is they drop at the same time and reach the bottoms of their swings at the same time) their CF would fight each other and the net down force would be 0 at all times.  There wouldn't be any force to produce or sustain the rocking motion.  That is if I am looking at the pictures correctly.