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Overunity Machines Forum



Kapanadze Cousin - DALLY FREE ENERGY

Started by 27Bubba, September 18, 2012, 02:17:22 PM

Previous topic - Next topic

0 Members and 89 Guests are viewing this topic.

AlienGrey

sounds like a phase shift thing if L and C have the same impedance
Ive just been setting up a ferrite toroid-like that this afternoon.
The drive into a resistive load is impressive at resonance so is the current

AlienGrey

Quote from: forest on February 22, 2019, 10:56:11 AM
Yes, every transformer is theoretically 200% efficient.
Oh yes?  how does that work then?

Do Tell !

Void

Quote from: Jeg on February 22, 2019, 10:46:12 AM
This is not quite true. At high power in iron transformers you can go at high efficiency levels close to 90%. But also by imposition I managed to go close to 1. See again my push pull device in my channel. Anyway. I have invented a new method for measurements. I'll call it CapIn/CapOut technique. I use two identical caps one for input and one for output. I charge the input cap from a battery and I discharge it through the circuit I am measuring. After I measure the voltage level of my output cap and here it is. If the output cap is at higher potential than the used input potential then something is going on. If not then I just move on without any doubts.


Hi Jeg. You did not 'invent' that. Such a method of comparing capacitor energy has been suggested
in these forums before. ;)

If you are comparing input and output capacitor voltages as you describe in your comment, that will be incorrect.
You must compare input capacitor energy loss to output capacitor energy gain, not compare cap voltages!

For example, let's say you are using two 100uF caps.
Input cap is charged to 12 Volts when starting. Output cap is at 0 Volts
When finished, input cap measures 6 Volts and the output cap measures 8 Volts.
Is this indicating over unity? The answer is No!

100uF cap at 12V is storing 7.2mJ
100uF cap at 6 Volts has 1.8mJ remaining.
Energy used at input is 7.2mJ - 1.8mJ = 5.4mJ
Output cap is 100uF at 8 Volts = 3.2mJ
The circuit used 5.4mJ, and the output cap ony gained 3.2mJ.

Also, transofrmers are of course not greater than 100% efficient. If they were,
all anyone would have to do is use a transformer and they would have COP > 1.
Which is not the case at all. :)



Void

Quote from: Jeg on February 22, 2019, 11:20:25 AM
If you make work with your primary charges instead of wasting them perhaps it is the basis behind everything here.

Hi Jeg. Common misconception here, it seems. To have 'over unity', the output
energy delivered to a load or storage capacitor of a circuit must be greater than the input energy
that was 'consumed'. You have to think in terms of energy input and energy 'consumption', not
in terms of currents or charges or that sort of thing.

If you put a load in series with the primary of a transformer, the primary winding and
the load will have a common current through them, but when you start looking at energy
'consumption'
, then you will see what the problem is. Same current through them, but the AC voltage
divides between them. There is less power input to the transformer primary winding, since the voltage
across the transformer has dropped due to the voltage drop across the load which is in series with the primary winding.
You can't fool nature. :)



Jeg

Hi Void
At least you could let me a day believing it was told for first time :D

Of course you are right about measuring energy instead of voltage. I was thinking my systems in which I use high side switching and the input cap goes up to zero volts. But again, If I start with a cap at 24v and I take for example 26V at the output, no matter how much left at the input cap then, we have something I guess.