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Overunity Machines Forum



Re-Inventing The Wheel-Part1-Clemente_Figuera-THE INFINITE ENERGY MACHINE

Started by bajac, October 07, 2012, 06:21:28 PM

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marathonman

Cadman, sorry i almost forgot about you.

the two top circuits will not work as they will block the inductive kickback from the receding electromagnet from reaching part G. nothing can be between the primaries and part G on the low side or self running will never take place.

gmolina


Cadman

Thank you MM.

I suspected the top two circuits were no good based on what you said earlier about the inductive kickback, but I wasn't sure.

So the bottom two circuits are viable.

I am aware that the diode bridge may not be a good means of rectification for this, but I want to try it anyway. I am referring to the Tesla patent for rectification that Doug spoke about. I hope that is not necessary.

So, judging from your reply to Sam6, heavier wire for the inductors, fewer turns, more amps, low inductance for rapid field response, no air gaps, more than two inductors to get the combined high output wattage.

That's a lot of information. Thank you very much!

gmolina

Quote from: Sam6 on July 28, 2016, 04:13:00 PM
My understanding of one of Faraday's experiments is that he pushed a bar magnet toward a loop of wire that had a galvanometer attached to the ends of the wire. When he pushed one pole of the magnet toward the wire, the galvanometer deflected in one direction, and when he retracted the magnet the galvanometer deflected in the opposite direction. The magnitude of the deflection was proportional to the rate of change of the flux through the loop.

If he went to the other side of the loop and caused the same pole of the magnet to approached the loop, the deflection of the galvanometer was opposite that of the initial approach deflection. In other words a magnet approaching a loop from the right produces the same deflection as a magnet receding from the left and vice versa.

My further understanding is that in a setup with 1) two bar magnets facing each other separated by a nonmagnetic bar glued between both like pole faces to keep them separated by a fixed distance and 2) a stationary loop with an attached galvanometer is wrapped around the nonmagnetic bar; if the magnets are moved back and forth, the galvanometer will move back and forth with twice the deflection magnitude as that of a single magnet moved at the same rate.

That says to me that Marathon Man is right: that the electric fields produced in a coil by two like poles of electromagnets facing each other when powered by voltages 90 degrees out of phase are additive.

With that in mind, I have attached a set of calculations for a single phase magnetic circuit based on that principle to produce 16KW. It appears that such a unit will fit in an area less than two feet square by a foot high, and weigh about 300 pounds. One of my major concerns is cooling requirements, as it will have losses amounting to about 1500 watts. I don't know how to calculate the temperature rise and would appreciate help in making that determination.

I have used the equations and methods outlined in some books that have been referenced earlier in this forum and are mentioned in the attached document. Because I want to have a proper understanding of the principles involved, I ask that forum members look the document over and point out errors due to improper logic, misunderstanding of principles, or stupidity. When exploring unfamiliar territory, I need all the help I can get. I would appreciate your comments, criticism, and corrections, as I am want all of us to be able to build these devices with defined outputs without having to mess around with trial and error.

Thanks in advance for your help.
Sam

Hi, please consider that Figuera is a DC device, can recalculate with the signals proposed in figure attached.

GM

Sam6

Marathon Man
Thanks for your comments. Since I seem to be suffering from an advanced case of optical recticosis, I would appreciate you sharing how you make the calculations for for your 20 KW unit so I can learn the correct method.
Thanks in advance for your help.
Sam