Re-Inventing The Wheel-Part1-Clemente_Figuera-THE INFINITE ENERGY MACHINE

[ALVARO_CS]

hi Hanon

I do not know how to measure the amperage of a current in an open loop. (no load)
Only know to put the ammeter in series with one of the two output wires when load is present closing the circuit. Also in series (inserted between one wire) before the device, to see input amperage. (eg. before a motor or a lamp)
IMHO, if the whole circuit is open at the end, (no load) no current is circulating.
The primary is closed: two leads live-return
The secondary is open: two leads no load
If the two secondary leads (in-out) were connected to the ammeter, it was shorted (closing the circuit) as has been stated in a previous post.

[NRamaswami]

Alvaro_CS:

Output wires were not connected to each other. They were connected to the load bulbs but because the voltmeter showed very high voltage, we did not switch on the lamps. It is at that point the ammeter showed 20 amps. Normally the Ammeter does not show any amps when no light is burning or even when two 200 watts lights are burning. Ammeter starts showing amperage only when 3x 200 watts lamps are burning and that is only around 1.5 amps. Although the lights are rated at 200 watts they consume less than 200 watts to light up.

When I said the secondaries were kept open I essentially indicated that the secondaries had no load on them and were open circuit. I apologize for any miscommununication on my part and please understand that neither is English my first language nor is this subject my basic expertise area and I readilly acknowledge that I do not know much..Forgive me for any mistakes in communication. Please..

[ALVARO_CS]

@NRamaswami

When there is such a good will as yours, no mistake can make an offense, so. . no apology nor forgiveness needed from both sides.

Anyway, thanks for the clarification

English is neither my mother language

regards

[gyulasun]

Hi NRamaswami,

You wrote:

Output wires were not connected to each other. They were connected to the load bulbs but because the voltmeter showed very high voltage, we did not switch on the lamps. It is at that point the ammeter showed 20 amps.

What you describe above is an impossible situation. If the load lamps were switched off, then there is no way the ammeter showed the 20 Amper current. And if it showed, then you somehow had a closed circuit in the secondary you were not aware of, please try to ponder on this. 
I am not saying you do some miscommunication here but you yourself should realize that it is impossible to have an open circuit at the output and still state the 20A current and state an output power with it.
It is okay if you calculated the current by linear interpolation (by mathematically) as you described it last night deducing the numbers from the input current and voltage hence input power but then it is not a measured power but a calculated one.


You also wrote:

Normally the Ammeter does not show any amps when no light is burning or even when two 200 watts lights are burning. Ammeter starts showing amperage only when 3x 200 watts lamps are burning and that is only around 1.5 amps. Although the lights are rated at 200 watts they consume less than 200 watts to light up.

I put in bold your first sentence above: the first part of your sentence is correct till the word or but the second part is not! When two 200 watts bulbs were burning the ammeter should have already shown a certain current but not zero! Maybe the ammeter was not connected correctly to measure the output current or it was not a dependable instrument? 
Normaly to get the load current at the output, you connect the ammeter in series with the bulbs or in series with the group of the bulbs and the series combination of the meter and the bulb(s) are connected across the output. Was this done so, can you recall?

Well, earlier you mentioned you had an analog meter and it burnt out. Before it burnt out, it must have been abused already because if it was correctly connected in series with the bulbs,  then it should have measured half an amp, one amp etc, any amps higher than zero, ok?

By the way, English is my second language.  I hope you understand it and then you could try to explain this output "mistery".  No problem that you are not an Electrical Engineer but you surely feel that when the bulbs were unconnected, then the 20A current had no way to flow in the secondary coil.

And I am trying to help with these posts and I hope you understand now how the output power is to be measured in the simplest way when you have an AC voltmeter and an AC ampmeter, hooked up at both the input side and the at the output side.  Ammeters always inserted in series with the input side and/or with the output side, this is the only way to get info on the input current draw and on the load current drawn by the bulbs at the output side.
IF something is not clear in this respect, please ask, and I can draw a simple sketch to show a measuring setup, basically it would reflect what I wrote so far.

Regards,  Gyula

[forest]

I see only one danger , (not real one but in interpretation) - if that 20Amps are at low voltage or in other words if output is mixed 630V low amps and some lower voltage 20 amps. Could it be ? Sorry, English is also not my primary language and I'm not electrical guy also...