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Has An Important Property Of Fluids Been Overlooked ?

Started by fletcher, November 16, 2012, 10:23:26 PM

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0 Members and 3 Guests are viewing this topic.

johnny874

Quote from: fletcher on November 23, 2012, 09:40:36 PM
Here Is My Concept & Theory In Short:

1. That buoyant force is a result of pressure differentials of which Archimedes volume displacement & uniform fluid density is a sub-set [see Archimedes Paradox re Hydrostatic Paradox].

2. That floatation is a function of buoyancy where buoyant force is in equilibrium with mass weight force.

3. That a mass buoyed by a contained fluid will create pressure in said fluid - the pressure will be transmitted undiminished to all parts of the fluid [as per Pascal's Principle] - the pressure distribution is effectively a redirection of the mass weight force evenly thru the fluid medium even though the weight is the sum of the parts [hydrostatic paradox] - that the greater the mass the greater will be the pressure increase & the buoyancy force [synchronicity].

4. That the torque on the ascending side of such a symmetrical structure will be less than the descending side.

5. That only the vertical component of gravity force is displaced in this way & the horizontal component has a normal effect on the structure, so the proposed Virtual Displacement of Mass effect is maximum at the horizontal orientation & diminishes accordingly.

  Fletcher,
I get what you are getting at here. I tried discussing something similar along time ago. No one got it.
I tried using 4 bellows, one every 90 degrees to explain how balance shifts. For the design I'm working on, I think you are the only who understood it. The difference with it is instead of pumping water across the wheel, it pumps it around the wheel. This maintains the imbalance as a maximum value of torque.
I think what everyone is missing when they look at your example is the volume being displaced. If water occupies 1,000 cubic centimeters per kilogram, then a cylinder 1/2 the size could move a little over 1 pound of water with a weight moving the distance
that H equals in PiR^2H=Vol. And if the weights weight 1/2 kg, then working together, the maximum amount of weight they can move is more than 1 kg. Water can also act on itself when moving downward.
The question to be asked then is how much does the movement of water slow when it is being moved through a tube ? If the tube is the same diameter as the weights or plungers, then it could move fairly quickly.

                                                                                                                    Jim           

Red_Sunset

Quote from: fletcher on November 23, 2012, 09:40:36 PM
....................................
4. That the torque on thes acending side of such a symmetrical structure will be less than the descending side.
.....................................................

Fletcher,

With further reference to post #23, tossing the idea over for a while,  need some more detail clarifications,

1..  In item #4,  what do you mean with "ascending and descending side" ? , can you define this better to avoid misunderstanding.

2.. Can you confirm that we have a balance of both Masses across the fulcrum ?  The target imbalance is the fluid across the fulcrum.  Can you confirm ?

3..  You also mention "Buoyancy is a function of prressure differential &................  " and " piston has equilibrium of forces,  buoyancy  and weight force"   So the mass is buoyant, and the mass movement effect is not gravity directly, instead it is buoyancy that is the controlling positional movement force ?  The visual picture doesn't seem to conspire to that.  Can you clarify ?

Regards, Michel

johnny874

  Fletch,
What everyone has missed about Bessler is that if a lever generates 4.9n-m of torque with a 1 kg weight,
with a 3:1 gear down (make 3 stones fly as 1), then you would have 14.7n-m of torque. And if the piston moves 2.5cm's and the 1 kg weight moves 7.5cm's, the fluid being pumped can be moved a greater distance which would all09ow for free energy.  Res sunset, if a weight drops 15 cm's on both sides of the fulcrum, it can move a volume of water PiR^2  15 cm's on the opposing side. If you have 1/2 kg of water, then with a weight moving 15 cm's, the center of mass of the water can be moved to the other side of the fulcrum.

                                                                                                                                    Jim

edited to add; Red Sunset, think of it this way, when the 2 weights on opposite sides of the wheel move downward, the over balance created by the water moves all the way across the wheel.

Red_Sunset

Quote from: johnny874 on November 26, 2012, 07:19:23 AM
  Fletch,
What everyone has missed about Bessler is that if a lever generates 4.9n-m of torque with a 1 kg weight,
with a 3:1 gear down (make 3 stones fly as 1), then you would have 14.7n-m of torque. And if the piston moves 2.5cm's and the 1 kg weight moves 7.5cm's, the fluid being pumped can be moved a greater distance which would all09ow for free energy.  Res sunset, if a weight drops 15 cm's on both sides of the fulcrum, it can move a volume of water PiR^2  15 cm's on the opposing side. If you have 1/2 kg of water, then with a weight moving 15 cm's, the center of mass of the water can be moved to the other side of the fulcrum.   Jim
edited to add; Red Sunset, think of it this way, when the 2 weights on opposite sides of the wheel move downward, the over balance created by the water moves all the way across the wheel.

Hi Jim,
I can see that the idea is to imbalance the water with the Masses, ok.
The mass movements are initiated / executed by weight (gravity) or buoyancy,  mass2 in the picture appears like held by weight (gravity) by the absence of buoyancy assuming a water sealed piston. Mass1 should take the same position than 2, if buoyancy is the force producer.
Just a matter of understanding the detail correctly
Michel


GreenHiker

I followed along with Fletcher's material from the Bessler wheel site,  until he got to the bouyant weight added to the fluid. It seemed to me that the buoyant weight would have an effect on the balance/weighting of the fluid. I was wrong. I balanced a 4 gallon pot, 3/4 filled with water, on a 3/4" nut (tippy) and pushed a tall (empty) one gallon pitcher down, and around in the pot slowly. It had no effect on the balance of the pot.

So moving right along, has anyone attempted a build yet?