1850 Watts free energy power ? New GEGENE circuit by JL Naudin shows COP = 2.8

[hartiberlin]

I remember hearing that these cheap digital Wattmeters also have problems
showing the real Wattage and Powerfactor,
when you use a dimmer circuit before a load, cause they can´t handle and measure correctly the
cutted sine waves from the dimmer...

Maybe it is the same problem in the Naudin and RomeroUK test with the GridTie Inverter ?

[hartiberlin]

Jean Louis has just posted a new Cold Fusion experiment with it
using the output coil as the power source:

http://jnaudin.free.fr/gegene/gegene14en.htm

Looks interesting, but he has not yet done any power measurements and efficiency tests.


Regards, Stefan.

[JouleSeeker]

They are notoriously bad.
Here is a quote from a review of one particular model:

"Getting technical for a minute, the one other thing that surprised me concerned the hob's power-factor. The manual correctly states that when on Standby, it only consumes about 1 watt. However due to its low power-factor, it's actually pulling over 150VA - basically, 150 watts that 'technically' you don't have to pay for, but the electricity supplier must still provide, in other words, wasted energy! And most should already realise that this kind as 'wastage' is already factored into your bill. And it's definitely not very 'environmentally-friendly'! The manual does mention though that the hob should be disconnected from the mains when not in use."

It's from here:
http://www.amazon.co.uk/product-reviews/B004BM749S

As I mentioned, this is gross measurement error - no magic just poor understanding.

Hold on.  Let's say one is simply heating a liter of water in a pan on an induction cooker.
We measure the heat OUTPUT by measuring the temp rise of the water.
Then Qout = 4.19 *(mass in g)* (Temp-rise in C).

We measure Pin using a power meter, preferably an "official" power meter supplied by the utility company.

Are you saying that the output energy (Qout) will be LARGER than the measured Pin?

[Madebymonkeys]

Hold on.  Let's say one is simply heating a liter of water in a pan on an induction cooker.
We measure the heat OUTPUT by measuring the temp rise of the water.
Then Qout = 4.19 *(mass in g)* (Temp-rise in C).

We measure Pin using a power meter, preferably an "official" power meter supplied by the utility company.

Are you saying that the output energy (Qout) will be LARGER than the measured Pin?

No, the output from this will always be lower than the input.
All I am saying is that the power results from this system aren't measured correctly and cannot be trusted. The power gains that JLN sees on those little Chinese screens can be explained by poor measurement methods.

[Madebymonkeys]

No, the output from this will always be lower than the input.
All I am saying is that the power results from this system aren't measured correctly and cannot be trusted. The power gains that JLN sees on those little Chinese screens can be explained by poor measurement methods.

When claiming gains like this and asking people to replicate, all it's doing is causing people to spend time on this rather than something useful!