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Overunity Machines Forum



Welcome to Understanding Overunity!!!!!

Started by wattsup, December 31, 2012, 04:11:07 PM

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Bob Smith

Quote from: vineet_kiran on December 31, 2012, 07:16:24 PM
Overunity cannot be achieved unless you eliminate the feed back force (reaction) which tries to slow down the applied force. 
One way to do this is with a bifilar secondary, which cancels out its own transverse EM waves, thereby preventing secondary reflection (from secondary to primary), and producing longitudinal (scalar) vectors. In this way, there is no dissipation/losses of energy in primary - i.e., it remains isolated.  If you look at Dave 45's diagram, the secondary is an open bifilar coil, which in theory, should not affect the primary with reflective losses.

The only other thing I would add about OU is that a system must remain open, imbalanced, to allow background/vacuum/ambient energy to continuously flow in. Many ways to skin this cat. Perhaps someone else can elaborate.
Respectfully, Bob

TinselKoala

The schematic Dave posted is the same basic circuit I have been using for some months now in my wireless power systems and my extreme flyback driver. It is also the same basic circuit as many induction furnaces. I don't see any "open bifilar secondary" in that diagram.

Also, I have to say....... voltage is charge pressure. It arises from the mutual repulsion of like unit charges, and in our normal experience this means electrons, the carriers of the unit negative charge. And current is the time rate of flow of charge past a measuring point. You cannot have a flow of charge -- a current -- unless you have a difference in charge pressure-- a difference in potential, or voltage. I think there are some misconceptions about voltage and current that are pretty common in this forum.

I also take issue with this statement:
QuoteOne way to do this is with a bifilar secondary, which cancels out its own transverse EM waves, thereby preventing secondary reflection (from secondary to primary), and producing longitudinal (scalar) vectors.
Do you mean a true Tesla bifilar connection, or a non-inductive hairpin connection? Certainly the Tesla connection does not "cancel its own transverse EM waves." The increased inter-turn capacitance of a true Tesla connection means that the coil's inductive and capacitive reactances can cancel without needing an external capacitor, if properly constructed, thus reducing its total impedance when compared to an ordinary coil of the same turns and length of wire, and allowing a given power source to produce a changing EM field -- transverse EM waves -- more efficiently. A Tesla bifilar connection does this not by lowering inductance as some people seem to believe, but by raising capacitance. The Tesla bifilar coil will still have plenty of inductance, in contrast to the hairpin connection which reduces inductance to nearly zero.

OK.... I realize I've probably violated a bunch of wattsup's rules by now, so I'll stop. But I like my drawing version of the Royer self-resonant zero-voltage-switching oscillator better than Dave's.   ;)

Carry on..... and I promise to stay quiet..... as long as I don't see too much outrageous stuff that I've already shown to be erroneous in my videos !!
:-X

Magluvin

Quote from: Dave45 on January 01, 2013, 01:54:33 PM
Idea's  ;D

Hey Dave

If so, would we be able to 'read' a difference in current between the red and yellow output lines?

Mags

Dave45

Quote from: Magluvin on January 01, 2013, 08:03:38 PM
Hey Dave

If so, would we be able to 'read' a difference in current between the red and yellow output lines?

Mags
I see what you are saying, I havent tried that, but it would only move through a load so could we really tell.
Here's one, find the frequency of the PM

Dave45