Rosemary Ainslie Circuit Demonstration June 29, 2013 Video Segments

[TinselKoala]

 

I have ALWAYS known that our CRS's can tolerate 25 watts each.

I'll ask poynt99 to comment on this statement from RA that she made today.

[TinselKoala]

The total circuit DC resistance of the Ainslie-Martin circuit is close to 13 ohms, if we can believe her specs for the "element resistor". 11 ohms for the element and 2 ohms for the mosfet Q1 fully turned on. If the Q2s could be fully turned on that would lower the resistance to about 11 1/2 ohms, but the circuit cannot turn the Q2s fully on.

Hence the total current flowing in the circuit, with a 6-battery stack fully charged to 78 volts, will be a maximum of  I = V/R == 78/13 == 6.0 Amperes.
In the Q1 fully on 100 percent of the time DC condition, the circuit will carry 6 amps, and the load will be dissipating P = I²R == almost 400 Watts. If the duty cycle is reduced to 10 percent, then the average dissipation in the load will be 40 Watts. For "upwards of 50 Watts" whatever that might mean... call it 55 Watts.... the duty cycle for Q1 ON time must be P_avg = (I²R)(duty cycle), so solving for Duty Cycle we have duty cycle = P_avg/(I²R) == 55/396 == about 14 percent.

So, with a full battery stack, a 14 percent Q1 ON time would produce 55 Watts average dissipation in the load. The Q2 oscillations contribute little or nothing to the heating of the load.

At 36 volts supply, the current would max out at 36/13 or 3 amperes, and carrying through the calculations again we have max power in the load, at 100 percent Q1 ON, of about 100 Watts. Reduce the duty cycle to 50 percent and you have 50 Watts dissipated in the load. No Q2 oscillations needed, nor do they contribute.

In the first case, 6 amps current at 100 percent ON, a 0.25 ohm Current Viewing Resistor will dissipate 6x6x0.25 == 9 Watts maximum. If the duty cycle is reduced the power dissipation of the resistor goes down proportionally.
In the second case, 3 amps current at 100 percent ON, a 0.25 ohm CVR will dissipate two and a quarter Watts. Reduce the duty cycle, and you reduce the power proportionally.

The oscillations are not providing any significant heating to the load. Most of the load heating is coming from the Q1 ON times. Much of the rest comes from the function generator or DC bias supply itself. A tiny bit comes from the oscillations causing the Q2s to dribble a bit of current.

Don't believe me? Set up your complete experiment, monitoring temps "over the load" as usual. Set your FG to your favorite "oscillation" settings to produce HIGH HEAT, 50 Watts or "upwards", in your load, and let the temperature stabilise. Now... without doing anything else, just unplug the DRAIN leads of all your Q2 mosfets. What happens to the load temperature?

Now start over, with everything hooked up, and use the same FG settings to make the same heat as before and let stabilize. Now, without doing anything else, just unplug the Drain lead of the Q1 mosfet. What happens to the load temperature?


This test would take a competent experimenter about an hour to perform, if that long. Who will be the first to do it? I'll tell you this much for nothing: it won't be Rosemary Ainslie or Donovan Martin -- but it just might be me, or .99, or some other rational experimenter who knows how to formulate and test an hypothesis.

[MileHigh]

TK and others:

The comedy show on the other channel continues.  Posie is all flustered about the CVR power issue.  We are still at the "start gate" if you will in the sense that she cannot understand that the voltages that she sees across the unwieldy CVR wiring in her setup don't correspond to the actual current flowing through the CVR.  This idea that the high speed switching is resulting in inductive di/dt "phantom voltage" in the CVR wiring is completely beyond her powers of conception.  Even if she was taught it the idea would only be retained for a few days anyways.

Meanwhile she is rude and says it's all "boring" and she must have already dropped that comment a half dozen times by now.

There is probably an interesting baseball stat out there...  Starting the clock from four years ago, Rosie Posie must have made at least 1000 errors, and perhaps one third of those errors are repeat errors.

So, it's gunna be "consistent sailing" as the ship slips over the horizon and finally falls of the cliff into the oblivion of obscurity.  The seasoned sailors can already smell that "end of the world" smell in the air.

MileHigh

[TinselKoala]

I would really like to see someone simply disconnect the scope probe from the current sense resistor entirely, and just clip that probe directly across a 220R , and then set it down in its normal position without actually connecting it to the board.

Now.... please explain to me this: If the oscillations that you see when the probe is connected to the circuit ARE ALSO SEEN WHEN IT IS NOT EVEN CONNECTED...  what exactly are you measuring, and how does it _really_ relate to the power in the circuit?


I have suggested test after test that would experimentally probe and reveal things about the circuit and the claims made. Poynt99 has done the same. When WE perform these tests on our apparatus, we get interpretable and repeatable results and we report them..... and they refute Ainslie's claims, each and every time. Yet Ainslie does not accept our results "for some reason." She appears to think that an identical circuit operated in identical ways, giving the identical data that she shows on the tests she HAS performed, will somehow act differently than hers does on these new tests. How does someone with gaps in thinking like that even manage to buy groceries?

[poynt99]

I'll ask poynt99 to comment on this statement from RA that she made today.

Rose was emphatic in stating that their resistors were rated only for 5W.

The power dissipated in the circuit series resistors are proportional to each other. So with an 11 Ohm load resistor and a 0.25 Ohm CSR, the CSR power dissipation will be 44 times less than the power dissipated in the load.

So if the load resistor is dissipating 55W, the CSR will be dissipating 1.1W.

I have confirmed a power test in a sim of the circuit; the load is 30W and the CSR about 0.7W. My load resistor is 10 Ohms, so the ratio is 1/40, not 1/44. So 30/40 = 0.75.