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Overunity Machines Forum



Tinman's Rotary Transformer

Started by tim123, September 02, 2013, 03:23:33 AM

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tim123

Hi Folks,
  I'm starting a new thread for this device because I think it does the 'impossible' - and uses the Lenz-force to aid the rotation - just like Tinman says.

The videos:

Part 1 - http://www.youtube.com/watch?v=yC4rCChVK8Y

Part 2 - http://www.youtube.com/watch?v=ZZixHuoVHxc

Torque Test - http://www.youtube.com/watch?v=x6xRcSkPYn4

RT Vs Motor Pt1 - http://www.youtube.com/watch?v=rVmVtRqwaRc

RT Vs Motor Pt2 - http://www.youtube.com/watch?v=szpJ97M58G4

Riding the Waves - http://www.youtube.com/watch?v=X163_IilwHk


Brief Description:

- The device is a modified 'Universal Motor' - i.e. a brushed motor that works with DC or AC

- The stator coils are disconnected from the input power. (They're usually connected to the brushes in series)

- DC or Rectified AC Power is provided in the usual way to the brushes. The motor turns by the attraction of the magnetised rotor to the iron stator.

- Power is taken off the stator coils, but only in the 'right' direction - via a diode.

- Increased load on the stators causes the motor to increase it's torque, it speeds up, and less input power is required.


Principle of Operation:

Here's how I think it works:

- The rotor segment is magnetised just before it enters the stator.
   It's attracted to the iron core of the stator.
   No power is taken off the stator at this point.

- The rotor segment enters the stator, providing torque...

- The rotor is depowered as it moves past the brushes, and the next rotor segment is powered up.

- The stator coil sees the 'loss' of flux, as the rotor segment in contact with it is depowered, so Lenz's law says it will attempt to reinforce that field.
   Now the power is taken off the stator coils...

- The stator produces a field of the *same polarity* as the rotor (was), in reaction to the loss of flux.
   So the stator then actively attracts the next rotor segment - for 'free'...



So the Lenz's Law / Back-EMF is acting in the same direction as the rotor. It's genius. :)

tinman

Quote from: tim123 on September 02, 2013, 03:23:33 AM
Hi Folks,
  I'm starting a new thread for this device because I think it does the 'impossible' - and uses the Lenz-force to aid the rotation - just like Tinman says.

The videos:

Part 1 - http://www.youtube.com/watch?v=yC4rCChVK8Y

Part 2 - http://www.youtube.com/watch?v=ZZixHuoVHxc

Torque Test - http://www.youtube.com/watch?v=x6xRcSkPYn4

RT Vs Motor Pt1 - http://www.youtube.com/watch?v=rVmVtRqwaRc

RT Vs Motor Pt2 - http://www.youtube.com/watch?v=szpJ97M58G4

Riding the Waves - http://www.youtube.com/watch?v=X163_IilwHk


Brief Description:

- The device is a modified 'Universal Motor' - i.e. a brushed motor that works with DC or AC

- The stator coils are disconnected from the input power. (They're usually connected to the brushes in series)

- DC or Rectified AC Power is provided in the usual way to the brushes. The motor turns by the attraction of the magnetised rotor to the iron stator.

- Power is taken off the stator coils, but only in the 'right' direction - via a diode.

- Increased load on the stators causes the motor to increase it's torque, it speeds up, and less input power is required.


Principle of Operation:

Here's how I think it works:

- The rotor segment is magnetised just before it enters the stator.
   It's attracted to the iron core of the stator.
   No power is taken off the stator at this point.

- The rotor segment enters the stator, providing torque...

- The rotor is depowered as it moves past the brushes, and the next rotor segment is powered up.

- The stator coil sees the 'loss' of flux, as the rotor segment in contact with it is depowered, so Lenz's law says it will attempt to reinforce that field.
   Now the power is taken off the stator coils...

- The stator produces a field of the *same polarity* as the rotor (was), in reaction to the loss of flux.
   So the stator then actively attracts the next rotor segment - for 'free'...



So the Lenz's Law / Back-EMF is acting in the same direction as the rotor. It's genius. :)
Hi Tim
You have one half of the operation worked out,now you just need the other half.
Hint-DC current is no good,it must be pulsed DC or Rectified AC-wich is kinda like a pulsed dc,only in a wave form.
The universal motor isnt so good for this sort of operation,but it's all i had at the time.The bigest problem is the over laping rotor winding's,and the fact that it is only a two pole motor.

Now what happens when you have two inductors facing each other(say a 3mm gap between them),one has a load placed across it,and the other is your primary(powered)inductor.Now hit the primary with a good sharp pulse of power-what dose the loaded secondary inductor do? Yes-it creates a backEMF against the primary inductor,or the lenz force effect.
So how do the magnetic fields cut through the above setup,that differs from a standard generator or altinator???.

tim123

I can't see ATM how rectified AC on the input will help. The change is too slow, and can't be sychronised with the rotor...

For example - take 50Hz AC - rectified = 100 pulses per sec.

If motor runs at 5000RPM (83.3Hz), and has 18 rotor poles (mine has 18) = (5000 / 60) x 18 = 1500 pole-changes per second

So each pulse covers 15 rotor-pole change-overs. So each rotor pole sees a more-or-less constant voltage throughout its 'powered-up' time. The pulses seem too slow to do anything but just reduce the overall throughput.

If the pulsing was important, surely it would have to be synchronised with the pulsing of the rotor / stator poles...?

I'm prepared to accept that pulsing may perhaps give better efficiency, but I think it will be at the expense of torque.

Quote"So how do the magnetic fields cut through the above setup,that differs from a standard generator or altinator???."

I think it doesn't have to cut through any fields - because they're all the same polarity. It's the clever (but simple) switching arrangement ensures the stator only ever goes to the same polarity as the rotor.

I'd like to see a comparison test of plain DC Vs. pulsed / rectified. I would definitely expect to see more rotary power out from plain DC than pulsed DC of the same voltage...

Magluvin

Quote from: tim123 on September 02, 2013, 01:20:14 PM


For example - take 50Hz AC - rectified = 100 pulses per sec.



Actually, it would be 50 pulses per sec. ;)

Mags

Magluvin

That is if it is half wave rectification. ;)   Which is it?

Mags