Reactive Generator Research for everyone to share

[wings]

"A Novel Transformer with Compensating Coil"
Xiaodong Liu 1*, Qichang Liang 2, Yu Liang 3
http://vixra.org/pdf/1204.0084v1.pdf

This is one by the same authors - it's a 'bucking coil' transformer - they say it'll power itself. It looks really simple, and totally illogical... The phrase 'retarded phase' seems to have been coined by the authors. I wonder if it's 'red herring' science for retarded people (like me)..?

The circuits in the other papers look simple to replicate, and one (1110.0004v1.pdf) looks a lot like what Luc is doing, but I'm concerned by the one I found above - it doesn't look right at all...

I'm also skeptical that simply moving a receiving antenna 1/4 wavelength from the source would result in OU (1104.0052v1.pdf). But again - it's an easy experiment...

JLN's LMD experiment is interesting, but if it's so obviously OU as claimed - why hasn't it been developed?

This whole reactive power discussion reminds me of rotoverters...

see hairpin circuit bulb in the water :
https://www.youtube.com/watch?v=XE5g6x6OOb0&feature=channel_page


https://www.youtube.com/watch?v=rDWF50fUoYY


http://www.overunity.com/7978/karl-palsness-hairpin-circuit/msg198582/#msg198582

[vince]

Now that Luc has left I was hoping someone else could help me.
I've have been trying out the reactive circuit that Luc suggested to start with, that is a MOT with capacitors in series to the primary and a resistor on the secondary.
My question is this.
Once I tune this to lowest input watts, hopefully 0, what does one do for the next step?
Say you want to place an induction motor or some other load in series with the input what does one do on the output.  I'm not sure if this has been pointed out or not but I don't recall seeing it.
Do you leave the resistor in on the secondary or do you substitute a high voltage capacitor? If so what value do you use as you just tuned the setup with a certain value resistor? Do you just short out the secondary?
Anybody have any insight on this?

[totoalas]

WITH O W INPUT  YOU CAN RUN THE INDUCTION MOTOR TO ROTATE THE GENERATOR AND SUPPLY THE INCOMING POWER LOOPED   

[Farmhand]

in the text :
The positive value of P1(t) represents energy flow
out of the source. The negative value denotes energy flow inward the source.

Yeah I understand what you are saying, and the intended meaning. But my understanding of the English language, the part in bold of the conclusion statement is an invalid statement.

Extracted means "taken out", so the energy is taken out of the source, ok so if energy is taken out of the source it cannot go out and in at the same time just because it's called negative.

It is unnecessarily obscure language, and I get suspicious when that happens. It may be negative in a momentary sense but when considered as net energy over a period of many cycles it must surely be positive.

If it was true then there would be a source of free energy, do it !

interesting:
Conclusion
In retarded resonance, the energy extracted from the source is determined by the retarded
phase on the route. When the distance between the source and the receiver is ¼ of
wavelength, the extracted energy from the source is negative.

Cheers

[hartiberlin]

I am refering to this video:
https://www.youtube.com/watch?v=byJ0Qo10g3o

Hmm, when looking at Luc´s scope waveforms and his videos where he showed
the scope shots, it gets clear, that he just phase shifts the current with this MOT resonance circuit.
So he has voltage and current almost 90 degrees out of phase, so the power factor is almost zero,
but there is still flowing a big current !

This is the case what power companies don´t like,  because the power is flowing back and forth between you and the power station and it just heats the transmission wires....and you have to pay also for this reactive power
cause the house meters register them !

So this is why you pay less, if you can make all your loads in your house
have a power factor of 1= no phase shift between voltage and current and then the energy only flows from the power plant to your home , but not back again...
( So the power company can use smaller diameter lines for the transfer of the power)

So for this case I don´t see any energy gain here.
The question is, if Luc is also resonating the MOT transformer at his 60 Hz grid frequency via his LC
tuning ?

Also the case when he powers the motor-generator with the additional MOT and cap bank at the motor input
could mean, that he is just using only a special impedance matching this way by "pre-equalizing" the motor
with reactive current and then also only drawing reactive power from output generator via the output MOT...

At least this motor generator combination needs around 184 Watts to run in idle mode, which is a lot of wasted energy
there, so combined with all the phaseshifts via the MOTs he might just use some kind of impedance matching, so that it looks like the Lenz law is violated.

The question for the case where the MOT and Caps are connected directly to the grid  and the output load is  connected
to the secondary, it would be interesting to see how many Watts exactly are extracted via the 2 bulbs and
what exactly the phase shift angle is between current and voltage and what the exact voltage and current values are in this case...so we could see and calculate the power factor and see, if there is indeed coming some free power out there due to some kind of resonance effect or so..

Regards, Stefan.