Mathematical Analysis of an Ideal ZED

[MarkE]

Lets just look and ringwall 2 shall we,,

It houses a riser and a water column,, R1 and AR3 if AR3 is at some height

59.293103mm

and then the Riser is stuffed in there and the water inside that Riser is at

1.420000mm

then the height of the missing water from ringwall 2 is

59.293103mm − 1.420000mm = 57.873103mm

and if R1 happens to have a diameter of 28mm then that is

.25π×28^2mm = 615.752160104mm

615.752160104×57.873103 = 35635.488184171mm^3

35635.488184171×.001 = 35.635488184cm^3

WOW,, did I just figure out the volume of the missing water inside ringwall2??

Looks that way to me.

Now what is it that that Archimedes guy said about the buoyant lift force??

That's right,, it equals the volume of displaced water.

If you want to figure out the correct answer then just answer each of the five questions.  Then maybe you will understand what you are doing wrong.  The up force on Riser1 side wall is the product of the pressure at the bottom of that side wall and the area of that wall's horizontal face.  It is no more and no less.  If the bottom of that wall is at 1mm (which it is) and the water level in AR2 is at 1.42mm (which you have stipulated) then the pressure transmitted from the top of the water column in AR2 to the underside, of Riser1 is not the same as the pressure acting on the bottom of the Riser1 side wall.  You can flail about all you want.  You cannot change that fact.

[MarkE]

So MarkE,

Should I be using the spreadsheet for this,, since in there you have the force needed to sink the open topped risers,, well that does displace water now doesn't it,, and then are you asking for the force relative to the air volume or the force for the entire volume of water that is being displaced.

What is "this" Tom?

You use it one way and then you use it the other,, so answer your own question first so we all can see which way you want to use your "special" rules of buoyancy.

What is "it" Tom?

Then again, I suppose you are calling TK's videos a fraud,, since those demonstrated that it is the volume of water displaced not what is displacing that water.

That does what Tom?  Why is it that you routinely fail to write intelligible English?  Is it the same reason that you write equations that miss the entire left hand side? 

[MarkE]

So MarkE can see the volume of displaced water

Oh joy!  You've posted a picture of more numbers on a page. 

[MarkE]

It's not the first time that someone has misinterpreted or overinterpreted what I show in a video. Maybe I need to use a different transcoder or something.

Aren't you going to answer the quiz? I'm dying to see if I got the same answers you did.

Tom seems decidedly reluctant to trying his hand at the quiz.  If one can answer the quiz questions correctly, then one should be able to understand why the R4 spreadsheet is correct and why Tom has been spewing a bunch of BS.

[celsus]

Hey MarkE,, Do you see the big error in your "quiz"

How do you displace that water with no change in the height of the surrounding water,, that must be more of your "special" skills,,,

You have made the water disappear,, like magic

Webby, those are two different drawings with two different waters. They don't have to drink from the same bottle necessarily