The Bessler Wheel, mystery solved.

[gurangax]

Is there anyone really familiar with the Bessler Wheel?  Some questions:  Do we KNOW that there is an axle that runs clear through the wheel?  If not, if it is possible that the inside is clear of anything jutting through the middle, that gives one more possibilities of what one can do.  If it does have an axle like that, there are still 2 possibilities.  Either the axle is solidly locked to the ground and does not rotate, and the wheel just rotates over it.  OR, the axle rotates with the wheel, which I suppose would mean the bearings would be outside of the wheel. Which is it? If the former, then that too presents some advantages, as now you have a solid non-moving structure inside the wheel to work with.

read here http://www.besslerwheel.com/wiki/index.php?title=Portal:Clues the axle have many compartments and holes and I may know why. Everything inside it rotates there is none that stays still.


regards

[Newton II]

Any static force that is not matched by an opposing static force results in acceleration in the direction of the imbalance, and consequently a reaction force equal to the product of the mass and the acceleration.

Just continue that argument.  When static force moves in the direction of imbalance,  the reaction force also moves in the direction of imbalance because they are in contact.  The product of positive force multiplied by displacement is useful work.  But what happens to the product of negative force (reaction) and displacement? 

[MarkE]

Just continue that argument.  When static force moves in the direction of imbalance,  the reaction force also moves in the direction of imbalance because they are in contact.  The product of positive force multiplied by displacement is useful work.  But what happens to the product of negative force (reaction) and displacement?

No, the integral of F*ds is work.  F is a vector.  Work is performed so long as motion occurs in the direction of the applied force.  There is no requirement that the force be positive with respect to any coordinate system.  Whatever applies force in the direction of motion conveys energy to anything that accelerates in the direction of the applied force.

[TheCell]

@gurangax
One weight on a lever provides torque on an axle ; at the end of the axle at the 2 Levers the torque is halved and because of the different length of these levers , the forces that they apply to the levers of the main shaft are not equal . Therefor they don't cancel each other and there is a resulting torque that rotates the main shaft. Please do not judge it based on his replication, but on the idea.
https://www.youtube.com/watch?v=OWRyYYX7JxE
Do you think this is possible?

[Newton II]

F is a vector.  Work is performed so long as motion occurs in the direction of the applied force.  There is no requirement that the force be positive with respect to any coordinate system.  Whatever applies force in the direction of motion conveys energy to anything that accelerates in the direction of the applied force.

Action and reaction are equal and opposite.  If you take vector sum of these two forces it accounts to zero.  Which means the mass shouldnot move at all.  But why a mass moves when you apply force on it?