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Overunity Machines Forum



Partnered Output Coils - Free Energy

Started by EMJunkie, January 16, 2015, 12:08:38 AM

Previous topic - Next topic

0 Members and 154 Guests are viewing this topic.

tinman

Quote from: EMJunkie on June 26, 2015, 10:22:34 PM
@Tinman - An extremely interesting answer!!!

I suggest you take some more time to think about the Magnetic Field. Break the Field down to the absolute Base Levels.

What is Entropy?

How is it that Earth's Magnetic Field has remained, through out its Cycles, for so long?

   Chris Sykes
       hyiq.org

What is there that could drain the energy that creates the earth's magnetic field's?

Why is it that the gravitational field travels faster than the speed of light?<-- you wont learn that in school.

As smart as we think we are,we still know so little<--or should i say,we are only allowed to know so little.

picowatt

Quote from: tinman on June 26, 2015, 10:23:55 PM
That is correct,and thus current cannot flow in the direction of the yellow arrow's(through coil A),but only in the direction of the red arrows(to the cap).

Tinman,

From your previous explanations, I understood the only effective current flow between coil B and the output side of the circuit to be that caused by inductive coupling thru the rotor and stator when coil B is shorted.

Given no other non-disclosed connections between coil B and the output side of the circuit, the current flow you indicate with the red arrows must also flow thru the resistor feeding the shorting circuit.

Is the resistor connected to a high impedance node in the shorting circuit? 

Please elaborate if you can...

PW

EMJunkie

Quote from: MarkE on June 26, 2015, 10:38:11 PM
Do you want to let on what that does to EMJ's most recent representation of what's in your shorting circuit box, or do you want to just let him continue to flounder?

@MarkE - This Thread must be one of your Favourites?

I need not implement any Guessing! I only question some explanations.

There in this above line contains more information than one may understand! But understand this and the rest is easy!

   Chris Sykes
       hyiq.org

EMJunkie

Quote from: picowatt on June 26, 2015, 10:43:36 PM
Tinman,

From your previous explanations, I understood the only effective current flow between coil B and the output side of the circuit to be that caused by inductive coupling thru the rotor and stator when coil B is shorted.

Given no other non-disclosed connections between coil B and the output side of the circuit, the current flow you indicate with the red arrows must also flow thru the resistor feeding the shorting circuit.

Is the resistor connected to a high impedance node in the shorting circuit? 

Please elaborate if you can...

PW

Here in lies PW's admission of incorrect understanding what was thus so firmly held on to!

Thank You PW!!!

tinman

Quote from: MileHigh on June 26, 2015, 10:39:24 PM
I note that even with S1 open you have a conduction path between the shorting coil and the load.  It's just an observation and I am not getting involved in the analysis.
Yes,there is a conduction path from coil B to the load,but no path from the load to coil B.
Coil B dose nothing until Coil A is producing a current flow,and thus S1 must be closed in order for coil B to provide current to follow that conduction path.