Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of these Archives, I am asking that you help him
by making a donation on the Paypal Button above.
You can visit us or register at my main site at:
Overunity Machines Forum



Partnered Output Coils - Free Energy

Started by EMJunkie, January 16, 2015, 12:08:38 AM

Previous topic - Next topic

0 Members and 109 Guests are viewing this topic.

MarkE

Quote from: EMJunkie on February 04, 2015, 06:27:17 AM
This should help as a guide:
Polarity dots on the windings would be nice.

That circuit as shown will generate lots of energy wasting, and instrument upsetting voltage spikes.  Circuit and instrument hook-up will each have a big effect on measured results.  The ceramic WW resistor is completely inappropriate for current sense.  A "non-inductive" (actually low inductance) current sense resistor should be used.  If an isolated differential probe is not available, then the low side of the current sense will have to be connected to the circuit common in order to establish the instrument common.  This will introduce a coupled loop through the wiring parasitics.

EMJunkie

Quote from: MarkE on February 04, 2015, 06:36:12 AM
Polarity dots on the windings would be nice.

That circuit as shown will generate lots of energy wasting, and instrument upsetting voltage spikes.  Circuit and instrument hook-up will each have a big effect on measured results.  The ceramic WW resistor is completely inappropriate for current sense.  A "non-inductive" (actually low inductance) current sense resistor should be used.  If an isolated differential probe is not available, then the low side of the current sense will have to be connected to the circuit common in order to establish the instrument common.  This will introduce a coupled loop through the wiring parasitics.

OOps, foot in mouth again MarkE - See the word "Load"? Fairly good indication its not a Current Sense Resistor!

But yes you're right about the other stuff... Yes, You're a bit on the smart side sometimes  ::)


MarkE

Quote from: EMJunkie on February 04, 2015, 06:40:31 AM
OOps, foot in mouth again MarkE - See the word "Load"? Fairly good indication its not a Current Sense Resistor!

But yes you're right about the other stuff... Yes, You're a bit on the smart side sometimes  ::)
You are as shrill as ever.  Since you had but the load resistor and it being highly inductive, my statement that it is not suitable as a current sense resistor stands.  The fact that you do not show a suitable current sense in your drawing raises question as to how you ever obtained measurements that led to your COP of 1.7 claims.  The CC-65 only has 20kHz bandwidth and its noise floor is about 10mA making it a very poor choice for looking at current.  Your voltage probe does not reference the voltage across the branch that you measure your current in, making power measurements based on the two useless.  Personally I think this has all just been your private joke on OU believers.

minnie




I get a great deal of enjoyment from this forum. Perhaps I learn the odd scientific fact but
far more than that is the insight into people's' ideas.
    Some just can't seem to understand the very basics and yet profess to be experts in a
particular topic. Some people can't be told and that's about it.
                  John.

TinselKoala

Quote from: MarkE on February 04, 2015, 07:15:43 AM
You are as shrill as ever.  Since you had but the load resistor and it being highly inductive, my statement that it is not suitable as a current sense resistor stands.  The fact that you do not show a suitable current sense in your drawing raises question as to how you ever obtained measurements that led to your COP of 1.7 claims.  The CC-65 only has 20kHz bandwidth and its noise floor is about 10mA making it a very poor choice for looking at current.  Your voltage probe does not reference the voltage across the branch that you measure your current in, making power measurements based on the two useless.  Personally I think this has all just been your private joke on OU believers.

(Emphasis mine)

I see you have beaten me to it. I was getting ready to post the same thing-- the probe connections as shown in the schematic do not appear to me to be a legitimate "output power" combination. That is a big Red Flag.

There also remains the question about whether the scope's channel "Probe attenuation" setting is even appropriate for the CC-65's 1mv=10mA voltage/current output. The scope's default is 10x. Is the channel set to 10x or 1x? Do we read the mV values indicated on the trace directly as mA, or do we have to include a factor or divisor of ten in the reading somehow? 

You know for sure that if I were doing tests like these, I'd show real comparison traces from the voltage drop across a proper inline current-viewing resistor compared to the CC-65's readout on the same circuit ... just as I did in the "pitfalls" video where I use both types of current sense systems on a Joule Thief, using the Lecroy DSO and a high-quality current probe. Which video also incidentally shows how just moving the voltage drop probe's ground lead three inches along the circuit wiring radically affects the amplitude of the measured signal.