Partnered Output Coils - Free Energy

[MarkE]

HI MileHigh. Like others here, you seem to be confused with what inventors do to market their inventions,
and what scientists do.  For certain an inventor had better be prepared to be able to prove their claims
to potential investors or people who may want to purchase the rights to their technology, but there is absolutely
no obligation for inventors to prove their inventions to the general public. Inventors do have to market their
stuff to find investors, such as releasing videos, for example. Who an inventor reveals specific details of their invention
to is totally up to the inventor however. Suggesting that the burden of proof is somehow on an inventor is only true
in their dealings with potential investors, and is usually done privately.
All the best...

LOL, no inventor here has ever proven in public or private that their free energy claims work.  EMJ has been taking people who are willing to follow his nonsense down a garden path.  He has expressed a hope that he can continue to do so for at least several more months.

It is an indisputable fact that the circuits that EMJ has published in their various incarnations transfer very little of the input energy to the output 10 Ohm resistor.  When the transistor is on, the output diode blocks, and only leakage currents flow.  When the transistor turns off flyback voltage equal to the difference voltage across the primary, less the diode drop appears across the circuit branch with the resistor.  Similar (but better) results can be realized without either of the output bucking coils.  The whole arrangement boilsdown to a badly designed flyback.

[MileHigh]

Conrad, EMJ:

The results just confirm what has been stated in many ways before.  The bucking coils turn what is ostensibly a 1:3 step-up transformer into a step-down transformer.  If the bucking coils are perfectly matched it would be a step-down-to-zero transformer.

So that implies a low value of resistance on the secondary to get more power going into the load.   You eventually run up against the wall of the total resistance of the two bucking coils being greater than the value of your load resistor.

Bucking coils simply are not bringing any value to the party...

MileHigh

[MarkE]

Conrad, EMJ:

The results just confirm what has been stated in many ways before.  The bucking coils turn what is ostensibly a 1:3 step-up transformer into a step-down transformer.  If the bucking coils are perfectly matched it would be a step-down-to-zero transformer.

So that implies a low value of resistance on the secondary to get more power going into the load.   You eventually run up against the wall of the total resistance of the two bucking coils being greater than the value of your load resistor.

Bucking coils simply are not bringing any value to the party...

MileHigh

Not quite, but close.  Because L2 is in series (via the diode) with L1, and both L1 and L3 connect to the supply voltage for N:1 turns on L2, and L3 versus L1 you have:

V_PRIMARY*(N+1) + V_SUPPLY - V_DIODE at TPA  and V_PRIMARY*(N) + V_SUPPLY at TPD on the other side of the 10 Ohm resistor branch.  The net difference is: V_PRIMARY - V_DIODE, not zero.

[Void]

Hi MarkE. I am convinced that if EMJ had simply just opened a thread and stated that he has been experimenting with
some interesting effects which he thinks may have some potential in regards to achieving over unity, then there likely would not
have been such an uproar and all the personal attacks and cheap shots against him by some here. We live and learn.
It is a good idea to tread carefully and use some tact when you may potentially be stepping on other people's dearly held beliefs.
I do agree with others that EMJ has not shown enough to make me personally think that he really did measure OU, as
there are so many potential ways for measurement error to creep in. IMO it is a very good idea to be very cautious about any measurements
before even thinking of claiming OU. Always the best to see if you can self loop a device before attempting to draw any conclusions
about OU. Making measurement errors or overlooking certain important factors is just too easy to do.
All the best...

[MileHigh]

Not quite, but close.  Because L2 is in series (via the diode) with L1, and both L1 and L3 connect to the supply voltage for N:1 turns on L2, and L3 versus L1 you have:

V_PRIMARY*(N+1) + V_SUPPLY - V_DIODE at TPA  and V_PRIMARY*(N) + V_SUPPLY at TPD on the other side of the 10 Ohm resistor branch.  The net difference is: V_PRIMARY - V_DIODE, not zero.

Conrad is testing on the original 100% passive transformer circuit.