Overunity motor, part3, all 4 recharging bats reading at 1.400 volts now.

[tinman]

Yes, and if you understood it in relation to this circuit you would realize that Miller capacitance suppresses switching:  rising collector voltage couples a rising base current which then passes emitter current that works against the rising voltage.  Miller capacitance can cause oscillations when the wiring is crap.  But before Miller capacitance can do a thing, you still need an energy source to drive current from the base to emitter.  Otherwise the collector just rides merrily along at the battery voltage.

Oh ok-so my circuit dosnt work then-->regardless of the fact that many have replicated it,and some are still running today.
Did you take into account the diode layer between the collector and base Mark when deciding that the miller effect would suppress switching. Both L1 & L2 have capacitance as well as inductance,so what happens in L1 when L2 switches off Mark?.

[PIH123]

Oh ok-so my circuit dosnt work then-->regardless of the fact that many have replicated it,and some are still running today.

Serious question:

If many have replicated it, why would only some be still running.
Shouldn't they all be still running. Or were the 3 dollars parts needed for another project ?

It is a serious question because it gets missed all the time. Something so simple, should either work or not.
Is there a gray area that can yield unpredictable results ?
Were the rest of the replicators not excited enough to show their results?
With the number of facebook postings and tweets going on each minute, we should be seeing this constantly in our feeds.

Thanks

Pete

[tinman]

I listed out the four possibilities and what each would imply.  If you have actual test data of a documented circuit including with pictures so we can see the "hidden circuit" caused by the wiring then we can analyze it and physics will as it always does, will once more prevail.

I guess this one would be as close as you got-->Circuit works with L1 near or far:  The transistor is receiving bias current from something other than L2 coupling to L1.

No hidden circuit caused by the wiring. You can place a small ceramic inductor(the ones that look like resistors) straight across the base/emitter if you like,and it will still work fine.

https://www.youtube.com/watch?v=5Mbp1iuB7as

[MarkE]

Oh ok-so my circuit dosnt work then-->regardless of the fact that many have replicated it,and some are still running today.
Did you take into account the diode layer between the collector and base Mark when deciding that the miller effect would suppress switching. Both L1 & L2 have capacitance as well as inductance,so what happens in L1 when L2 switches off Mark?.

I listed the four possible experiment observations with the two variables, and what each possible observation would imply.  If you have conducted such tests then kindly produce at least one clear photograph of the test set-up with L1 isolated.

I trust that you appreciate that an oscillator requires positive feedback. Absent positive feedback, the signal does not build-up.  Miller capacitance introduces negative feedback.  Miller capacitance can still contribute to oscillations when other circuit elements shift the phase sufficiently.  That happens typically with MOSFETs where there is lots of Miller capacitance and high gain bandwidth product.  The Miller capacitance then reacts with excessive inductance in the gate drive circuit generating the necessary phase shift.

As Pomodoro has said several times now, positive feedback can be generated with inductance in the emitter (bipolar) or source (MOSFET) lead.  That in fact was a source of oscillations in the Rosemary Ainslie fixtures that had atrocious wiring.  However, those oscillations did not start until there was sufficient gate to source drive in the first place.  For a 2N2222A or similar transistor which has a so-so gain bandwidth product of around 300MHz, and tiny parasitic capacitances that transistor is politely behaved in most hand wired circuits with several inches of wiring to each lead.  It takes a lot of emitter wiring inductance to get anywhere near the kind of time constant in the parasitics that is long enough for the transistor to amplify.

[MarkE]

I guess this one would be as close as you got-->Circuit works with L1 near or far:  The transistor is receiving bias current from something other than L2 coupling to L1.

No hidden circuit caused by the wiring. You can place a small ceramic inductor(the ones that look like resistors) straight across the base/emitter if you like,and it will still work fine.

https://www.youtube.com/watch?v=5Mbp1iuB7as

In that video Lidmotor states that he moved the inductor using clip leads.  Clip leads make great antennae.  The test that you want to run is much as ZFF suggested:  Put L1 in a Faraday cage, or better yet, take a twisted pair from Q1 base and emitter over to L1 just far away and/or in a Faraday cage.