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Overunity Machines Forum



A3C & X-MAGNETS AND PMF.

Started by ageofmagnetizm, May 19, 2017, 08:07:51 PM

Previous topic - Next topic

0 Members and 3 Guests are viewing this topic.

citfta

Quote from: ageofmagnetizm on May 18, 2018, 02:00:15 PM
I love english saying:


"We pay no hids for a wigs".


And everybody have to understand that as moderator
I have responsibilities which comes with enforcement gears
which I've deployed for the first time here, and if there are any
parties, groups or bands of interests - then they shoud enjoy own
discussions and let others enjoy theirs.


Is not it natural among gentelmens?

What you obviously don't get is that Gyula had no obligation to try and help you.  He tried to help because he is a gentleman and a scholar and wanted to give you some useful advice.  Those of us that really care about this hobby and pursuit of  free energy want to see others succeed also.  So we try to help when we can.  But there are always those that refuse help because they insist they know more than others.  Most of us on this forum actually appreciate help from others.  I have over 50 years experience in electronics but I am still willing to listen to others because NONE of us know everything.

Now go ahead and use your moderator privileges you claim you have and delete my post.  I'll bet you can't.

ageofmagnetizm

The last trying to help was 28 of april on the first page here:


"IT is very probable that a useful load when you connect it across the output coil will impose a drag on your drill, making it draw higher current from its own 10.8V Li-Ion battery hence input power would increase."

When I released videos of testing with loads then following five pages where intentionally produced psevdo-discussions
about simple matters disabling to discuss generators but dragging into chaos. That what people call: trolling.

Anyway, stop helping where you ra not welkom and start to do it where you are wanted.
That is so simple.

sparkmen

dear ageofmanetzm,
calling trolls the people that wants to help or need  to see proper measurment doen not make your device work better.
horse blinds are keept for a reason, you may keep yours
rgds,
mb

gyulasun

ageofmagnetizm:

Just go and report me, here is the next "harassment", LOL: 

In your blog, you wrote about "load" tests, I quote: "Many similar tests with various loads has produced
the same result and on following picture generator is testing with certifyed 100 ohms / 500 watts immersion
water heater where AC current causes increase of temperature of thermoelectric resistor where rising
temperature causes increase of resistance of electric circuit."
I took a snapshot at video time 2:35 from your revelant short video you referred to in connection with
the immersion water heater above. It is ok that you wrote 100 Ohm for the heater resistance and the
DMM resistance meter measured it as 80 Ohm in the video, this is not a problem. Your picture at the bottom
of your blog shows 534 Ohm and if we substract from 534 the 448 Ohm coil DC resistance, we get 86 Ohm for
the heater resistance. Again, the 80 and 86 or just the 77 Ohm as you mentioned at the bottom of the blog
for the heater is not a problem. It is also ok that such immersion water heater may change its resistance
a few percent from its cold resistance when it is performing real work by boiling up water to 100 degree Celsius.
The problem is that you imply you did load tests with such immersion water heater when your video clearly shows
the heater (with its points A and B) is connected via the DMM (that has B and C) to the generator coils output (A and C)
i.e. the DMM is set to AC Volt position and in this position the internal resistance of the DMM is about 1 MegaOhm. 
You closed the circuit between the generator output and the heater with the 1 MegaOhm internal resisance of your
DMM when set to AC Volt position.
Please answer this question: How can the heater boil up any single drop of water when you feed it
via a 1 MegaOhm voltmeter?  What current do you think can flow via the voltmeter's internal resistance?
If you connect the heater to the 230V mains voltage, the current draw would be 500W/230V=2.17 Amper
if I consider the heater to be a 500W heater, manufactured as such.
If you connect your heater via the voltmeter, the dissipated power in the heater is about in the microwatt range.

Now I repeat: go and report me for harassing you. 
It is YOU who harass readers here with bad science and not willing to show correct measurements.
You do not welcome members here who ask revealing questions that you carefully avoid answering.  Why is that? 

Gyula

ageofmagnetizm

Trolls have been reported five days ago and are on watchlists of NSA AIs which
have traced them down to nods and watching all theirs contacts, frequency of posts,
filming them on local CVRs and collecting information about theirs troll factories.


That how it works in contemporary reality.