Who would you like to witness a self-runner?

[Theoretical Research]

This post proves you don't know much about electrical engineering.

ps, I'll save you the time. The 0.9KV you talk about is more like 1.10KV across the capacitor and 1.12KV across the inductor, while the voltage from the free energy source is about 10mV (10E-3 V, 0.01 V). What academic are you? No offense, but it's obviously not electrical engineering. Lets save our time here and end this nonsense unless you want to prove to a lot of people you're an agent.

It's okay, but please learn at school or on your own. Not at the cost of others. Or maybe that's your goal.

[Magluvin]

If humanity isn't ready now, it won't be any more ready in 3 years.

My guess is that it doesn't work dependably.

Tesla said it in an interview way back then, 'There is no better time than now' when asked if he thought the world was ready for free energy.    And I agree

Mags

[blueplanet]

You're academic?? Show the math. 2A @ 0.9KV? Kilowatts? Oh my. Academics would understand a basic concept called phase angle taught in 101 electronics. I've already shown my math. Point out the error in my math. Show your math and  I'll point out your error. smh

It is not from my maths. I actually ran LTspice simulation on your circuit. I agree that the power at B2 is most likely zero. However, the steady current of B2 was about 2A. This much current is unlikely from space waves. As I said, I am interested in your air-core. If there is any secrecy concerned, you can PM me.

[Theoretical Research]

The 2A is caused by the oscillator. Again, please learn basic 101 electronics before making such statements.

[Theoretical Research]

Tesla said it in an interview way back then, 'There is no better time than now' when asked if he thought the world was ready for free energy.    And I agree

Mags

Yup. I'm more of an Einstein guy, who later greatly regretted helping scientists and engineers develop the nuclear bomb.